我知道在互联网上有很多例子,但没有一个做我真正想要的。我想选择多个图像的意图,并得到它的“网址”就像这样的代码与一个。 (我知道,这个代码不能超过一个选择,但我用这个作为例子的什么,我试图做)从android图库中选择多个图像并获取它的路径
代码:
public static final int RESULT_LOAD_IMG = 0;
public void LoadImg() {
Intent galleryIntent = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
startActivityForResult(galleryIntent, RESULT_LOAD_IMG);
}
ArrayList<Part> files = new ArrayList<>();
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == RESULT_LOAD_IMG && resultCode == RESULT_OK && null != data) {
Uri selectedImage = data.getData();
String[] filePathColumn = {MediaStore.Images.Media.DATA};
Cursor cursor = getContentResolver().query(selectedImage,
filePathColumn, null, null, null);
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
String picturePath = cursor.getString(columnIndex);
files.add(new FilePart("uploadedfile[" + String.valueOf(files.size()) + "]", new File(picturePath)));
cursor.close();
}
}
在互联网上搜索,我发现从Laith这个例子Mihyar在这篇文章中:Select multiple images from android gallery 我想在这里做同样的事情,但文件路径不同,并且我不想为我正在做的事情工作。
代码:
int PICK_IMAGE_MULTIPLE = 1
String imageEncoded;
List<String> imagesEncodedList;
Intent intent = new Intent();
intent.setType("image/*");
intent.putExtra(Intent.EXTRA_ALLOW_MULTIPLE, true);
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent,"Select Picture"), PICK_IMAGE_MULTIPLE);
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
try {
// When an Image is picked
if (requestCode == PICK_IMAGE_MULTIPLE && resultCode == RESULT_OK
&& null != data) {
// Get the Image from data
String[] filePathColumn = { MediaStore.Images.Media.DATA };
imagesEncodedList = new ArrayList<String>();
if(data.getData()!=null){
Uri mImageUri=data.getData();
// Get the cursor
Cursor cursor = getContentResolver().query(mImageUri,
filePathColumn, null, null, null);
// Move to first row
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
imageEncoded = cursor.getString(columnIndex);
cursor.close();
}else {
if (data.getClipData() != null) {
ClipData mClipData = data.getClipData();
ArrayList<Uri> mArrayUri = new ArrayList<Uri>();
for (int i = 0; i < mClipData.getItemCount(); i++) {
ClipData.Item item = mClipData.getItemAt(i);
Uri uri = item.getUri();
mArrayUri.add(uri);
// Get the cursor
Cursor cursor = getContentResolver().query(uri, filePathColumn, null, null, null);
// Move to first row
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
imageEncoded = cursor.getString(columnIndex);
imagesEncodedList.add(imageEncoded);
cursor.close();
}
Log.v("LOG_TAG", "Selected Images" + mArrayUri.size());
}
}
} else {
Toast.makeText(this, "You haven't picked Image",
Toast.LENGTH_LONG).show();
}
} catch (Exception e) {
Toast.makeText(this, "Something went wrong", Toast.LENGTH_LONG)
.show();
}
super.onActivityResult(requestCode, resultCode, data);
}
感谢
为什么不起作用?你想做什么?相当模糊的一切。当文件路径不同时有什么问题?不清楚。 – greenapps
我需要获取文件的路径,但是当我尝试使用第二个文件时,我得到一个应用程序名称(如com.appname.x)和一个带有id的文件,而不是我想要的路径得到。我试图得到这样的东西:“/content/files/image.png”,我得到“com.company.appname /&file6647”或类似的东西 – PaulD
你需要什么文件的路径?使用uri!你可以用它做任何事情。您想做什么? – greenapps