0
我通过Bonjour发送一些数据:NSData合并在一起?
NSString *songString = [NSString stringWithFormat:@"sn:%@", [bHelp song]];
NSString *artistString = [NSString stringWithFormat:@"an:%@", [bHelp artist]];
NSData *imageData = [self PNGRepresentationOfImage:[bHelp getArtwork]];
NSData *songData = [songString dataUsingEncoding:NSUTF8StringEncoding];
NSData *artistData = [artistString dataUsingEncoding:NSUTF8StringEncoding];
[self.server sendData:songData error:nil];
[self.server sendData:artistData error:nil];
[self.server sendData:imageData error:nil];
然后接受它:
NSString *message = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
UIImage *image = [[UIImage alloc] initWithData:data];
if (message != nil) {
NSLog(message);
if ([message hasPrefix:@"sn:"]) {
_songName = [message stringByReplacingOccurrencesOfString:@"sn:" withString:@""];
} else if ([message hasPrefix:@"an:"]) {
_artistName = [message stringByReplacingOccurrencesOfString:@"an:" withString:@""];
}
return;
}
if (image != nil) {
self.albumImage = image;
return;
}
但songData
,artistData
和imageData
都收到一个。一个例子是:sn:BURN IT DOWNan:Linkin Park
如果我先发送imageData
,它永远不会识别songData
和artistData
。如果我最后送imageData
,songData
和artistData
被捣成泥一起imageData
决不会被识别。
为什么有一个方法调用所有数据与多个调用与每个发送的数据包? @rmaddy – vqdave 2013-02-09 20:29:41