我正在使用codeigniter框架来开发我的网站。目前,我使用jQuery发送一个AJAX请求以从服务器获取数据。我试过两种方法,一种是数据在PHP关联数组中,另一种是在JSON对象中。请看到我从AJAX请求返回的数据:如何在codeigniter中获取json对象的值
{
"o": [
{
"q_id": "83",
"t_id": "4",
"question": "jjjjs.jfdaskldjf",
"option1": "jjjjasdfasdf",
"option2": "jjj",
"option3": "lll",
"option4": "lll",
"answer": "lll",
"marks": "22"
},
{
"q_id": "84",
"t_id": "4",
"question": "This is testing",
"option1": "2",
"option2": "7",
"option3": "8",
"option4": "9",
"answer": "2",
"marks": "2"
},
{
"q_id": "85",
"t_id": "4",
"question": "hello this is another test",
"option1": "a",
"option2": "b",
"option3": "c",
"option4": "d",
"answer": "a",
"marks": "2"
},
{
"q_id": "86",
"t_id": "4",
"question": "another test",
"option1": "8",
"option2": "9",
"option3": "0",
"option4": "1",
"answer": "1",
"marks": "2"
},
{
"q_id": "87",
"t_id": "4",
"question": "last question ",
"option1": "z",
"option2": "x",
"option3": "c",
"option4": "v",
"answer": "c",
"marks": "2"
}
]
}
我访问它:
alert(data["o"][0]);
但出现的错误是:
Uncaught TypeError: Cannot read property '0' of undefined
任何人都可以给我一些关于如何获取值或将对象存储在数组中的建议。
你可以发布让服务器发出ajax请求的jQuery代码吗? – james246 2013-02-09 17:10:03