MySQL的比较两个表，并添加缺少的值

Question

我有一个表ps_feature：

------------- 
|id_feature | 
------------- 
|1   | 
|2   | 
|3   | 
|4   | 
|5   | 
|6   | 
------------- 

，并用表ps_feature_lang：

-------------------------------- 
|id_feature | id_lang | name | 
-------------------------------- 
|1   | 1  | text1 | 
|2   | 1  | text2 | 
|4   | 1  | text3 | 
|5   | 1  | text4 | 
-------------------------------- 

是否有一个MySQL脚本在phpMyAdmin运行比较两个表并在ps_feature_lang中添加缺少的值？

结果应该是：

-------------------------------- 
|id_feature | id_lang | name | 
-------------------------------- 
|1   | 1  | text1 | 
|2   | 1  | text2 | 
|3   | 1  | N/A | 
|4   | 1  | text3 | 
|5   | 1  | text4 | 
|6   | 1  | N/A | 
-------------------------------- 

感谢。

Answer 1

要完成一个单一的语言，你可以使用的left join

insert into ps_feature_lang 
select f.id_feature, 1, 'N/A' 
from ps_feature f 
left join 
     ps_feature_lang fl 
on  f.id_feature = fl.id_feature and 
     fl.id_lang = 1 
where fl.id_feature is null