亲爱的,我想显示谷歌地图上我的应用程序正在模拟器上运行...但哪个api键我没有工作,并在模拟器只有瓷砖显示不地图显示什么要在我的模拟器中显示地图,我在android和java中都是新的,所以请简要地介绍一下exlinse中的thanklin ...我已经阅读了“获取MD5指纹”,但没有站在如何实现它,所以逐步解释.. .PLS PSL请.. 我的main.xml是什么是关键商店和如何实施谷歌地图
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/mainlayout"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >
<com.google.android.maps.MapView
android:id="@+id/mapview"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:clickable="true"
android:enabled="true"
android:apiKey="0mT--u1GbHdhnBJgPZU8zhoF2e4qdpCag32e7lQ" />
和java文件
package de.vogella.android.locationapi.maps;
import android.content.Context;
import android.location.Location;
import android.location.LocationListener;
import android.location.LocationManager;
import android.os.Bundle;
import android.widget.RelativeLayout;
import com.google.android.maps.GeoPoint;
import com.google.android.maps.MapActivity;
import com.google.android.maps.MapController;
import com.google.android.maps.MapView;
public class ShowMap extends MapActivity {
private MapController mapController;
private MapView mapView;
private LocationManager locationManager;
public void onCreate(Bundle bundle) {
super.onCreate(bundle);
setContentView(R.layout.main); // bind the layout to the activity
// create a map view
RelativeLayout linearLayout = (RelativeLayout) findViewById(R.id.mainlayout);
mapView = (MapView) findViewById(R.id.mapview);
mapView.setBuiltInZoomControls(true);
mapView.setStreetView(true);
mapController = mapView.getController();
mapController.setZoom(14); // Zoon 1 is world view
locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0,
0, new GeoUpdateHandler());
}
@Override
protected boolean isRouteDisplayed() {
return false;
}
public class GeoUpdateHandler implements LocationListener {
@Override
public void onLocationChanged(Location location) {
int lat = (int) (location.getLatitude() * 1E6);
int lng = (int) (location.getLongitude() * 1E6);
GeoPoint point = new GeoPoint(lat, lng);
mapController.animateTo(point); // mapController.setCenter(point);
}
@Override
public void onProviderDisabled(String provider) {
}
@Override
public void onProviderEnabled(String provider) {
}
@Override
public void onStatusChanged(String provider, int status, Bundle extras) {
}
}
}
我投票关闭这一问题作为题外话,因为它很旧,根据特征的弃用目前并不合适,所以它没有更多的有用.. – SRam 2015-06-10 12:22:47