2017-03-07 57 views
0

我需要构建下表。如何使用不同的where子句检索多个列计数?

<style type="text/css"> 
 
.tg {border-collapse:collapse;border-spacing:0;} 
 
.tg td{font-family:Arial, sans-serif;font-size:14px;padding:10px 5px;border-style:solid;border-width:1px;overflow:hidden;word-break:normal;} 
 
.tg th{font-family:Arial, sans-serif;font-size:14px;font-weight:normal;padding:10px 5px;border-style:solid;border-width:1px;overflow:hidden;word-break:normal;} 
 
.tg .tg-baqh{text-align:center;vertical-align:top} 
 
.tg .tg-lap0{font-size:100%;text-align:center;vertical-align:top} 
 
.tg .tg-yw4l{vertical-align:top} 
 
</style> 
 
<table class="tg" style="undefined;table-layout: fixed; width: 593px"> 
 
<colgroup> 
 
<col style="width: 67px"> 
 
<col style="width: 72px"> 
 
<col style="width: 116px"> 
 
<col style="width: 116px"> 
 
<col style="width: 116px"> 
 
<col style="width: 106px"> 
 
</colgroup> 
 
    <tr> 
 
    <th class="tg-lap0">State</th> 
 
    <th class="tg-baqh">City</th> 
 
    <th class="tg-baqh">Three Days Ago</th> 
 
    <th class="tg-baqh">Two Days Ago</th> 
 
    <th class="tg-baqh">One Day Ago</th> 
 
    <th class="tg-baqh">Total</th> 
 
    </tr> 
 
    <tr> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    </tr> 
 
    <tr> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    </tr> 
 
    <tr> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    </tr> 
 
    <tr> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    <td class="tg-yw4l"></td> 
 
    </tr> 
 
</table>

状态城市是简单的选择,但three_days_ago,two_days_ago,one_day_ago是DB条目同一城市名称的次数。 所有这些都在DB中的同一个表中。

所以我像我的查询像这样的事:

$union = pg_query($db, 
" 
(
SELECT estado, municipio, COUNT(*) 
FROM focos_bdq 
WHERE bioma LIKE 'Amazônia' 
AND satelite LIKE 'AQUA_M-T' 
AND data_hora_gmt::date='$three_days_ago' 
GROUP BY municipio, estado 
ORDER BY COUNT(*) DESC 
) 
UNION ALL 
(
SELECT estado, municipio, COUNT(*) 
FROM focos_bdq 
WHERE bioma LIKE 'Amazônia' 
AND data_hora_gmt::date='$two_days_ago' 
GROUP BY municipio, estado 
ORDER BY COUNT(*) DESC 
) 
UNION ALL 
(
SELECT estado, municipio, COUNT(*) 
FROM focos_bdq 
WHERE bioma LIKE 'Amazônia' 
AND data_hora_gmt::date='$one_day_ago' 
GROUP BY municipio, estado 
ORDER BY COUNT(*) DESC 
) 
" 

但这查询导致一个很长的表,当我需要把日期在同一行。

+0

编辑你的问题,并提供样本数据和期望的结果*文本格式*所以它是可读的。 –

+0

伙计们,感谢您的关注。 它已通过PHP中的后处理解决了... –

回答

0

很难说没有实际的数据,这样的事情应该做的伎俩:

with 
3d as (
SELECT estado, municipio, COUNT(*) 
FROM focos_bdq 
WHERE bioma LIKE 'Amazônia' 
AND satelite LIKE 'AQUA_M-T' 
AND data_hora_gmt::date='$three_days_ago' 
GROUP BY municipio, estado 
ORDER BY COUNT(*) DESC 
) 
, 2d as (
SELECT estado, municipio, COUNT(*) 
FROM focos_bdq 
WHERE bioma LIKE 'Amazônia' 
AND data_hora_gmt::date='$two_days_ago' 
GROUP BY municipio, estado 
ORDER BY COUNT(*) DESC 
) 
, 1d as (
SELECT estado, municipio, COUNT(*) 
FROM focos_bdq 
WHERE bioma LIKE 'Amazônia' 
AND data_hora_gmt::date='$one_day_ago' 
GROUP BY municipio, estado 
ORDER BY COUNT(*) DESC 
) 
select estado, municipio, d3.count,d2.count,d1.count,d3.count+d2.count+d1.count 
from d3 
left outer join d2 on d3.estado = d2.estado and d3.municipio = d2.municipio 
left outer join d1 on d1.estado = d2.estado and d1.municipio = d2.municipio