HTML和PHP分页工作不正确

Question

我有一些代码可以从数据库中提取所有结果并显示与用户搜索相关的结果。我还有一些代码可以计算项目数量，并根据与用户搜索相关的项目数量生成一定数量的页面。问题如下。如果我全部搜索，我的代码会在11个页面上显示数据库中的所有内容。如果我搜索汽车，它仍然会显示11页，但只有2个结果在标题中包含汽车。问题是这些结果显示在第八页上，而其他所有页面都是空白的。在第八页显示的标题中搜索汽车所有的两个结果。搜索全部基于数据库中项目的顺序。这里是我当前的代码：

   $pagesQuery = mysql_query("SELECT count(id) FROM(`posts`)"); 
       $pageNum = ceil(mysql_result($pagesQuery, 0)/5); 
       $start = (($page-1)*5); 


       $currentname = mysql_query("SELECT * FROM posts LIMIT $start, 5"); 
       while ($row = mysql_fetch_array($currentname)) { 
         //recieve relevant data. 
         $title = $row[0]; 
         $desc = $row[13]; 
         $ID = $row[6]; 
         $views = $row[3]; 
         $user = $row[7]; 
         //fetch the last id from accounts table. 
         $fetchlast1 = mysql_query("SELECT * FROM allaccounts WHERE id=(SELECT MAX(id) FROM allaccounts)"); 
         $lastrow1 = mysql_fetch_row($fetchlast1); 
         $lastid1 = $lastrow1[6]; 
         //acquire the username of postee. 
         for ($i1=1; $i1 <= $lastid1; $i1++) { 
          $currentname1 = mysql_query("SELECT * FROM allaccounts WHERE id=$user"); 
          while ($row1 = mysql_fetch_array($currentname1)) { 
           $username1 = $row1[0]; 
          } 
         } 

         //Format Title, description and view count. 
         $title2 = rtrim($title); 
         $donetitle = str_replace(" ", "-", $title2); 
         $url = "articles/".$ID."/".$donetitle.""; 

         $donetitle = strlen($title) > 40 ? substr($title,0,40)."..." : $title; 
         $donedesc = ''; 

         if(strlen($desc) > 150) { 
          $donedesc = explode("\n", wordwrap($desc, 150)); 
          $donedesc1 = $donedesc[0] . '...';       
         }else{ 
          $donedesc1 = $desc;       
         } 
         $finviews = number_format($views, 0, '.', ','); 

         //Give relevant results 
         if(stripos($title, $terms) !== false || stripos($desc, $terms) !== false || stripos($username1, $terms) !== false){ 
           if($row[10] == null){ 
            $SRC = "img/tempsmall.jpg"; 
           }else{ 
            $SRC ="generateThumbnailSmall.php?id=$ID"; 
           } 
           echo "<div id = \"feature\"> 

             <img src=\"$SRC\" alt = \"article thumbnail\" /> 
             </div> 
             <div id = \"feature2\"> 
              <a href= \"$url\" id = \"titletext\" alt = \"article title\">$donetitle</a> 
              <p id=\"resultuser\" >$username1</p> 
              <p id=\"resultp\">$donedesc1</p> 
              <a href = \"sendflag.php?title=$title&url=$url&id=$ID&userid=$user\" id = \"flag\" alt = \"flag\"><img src=\"img/icons/flag.png\"/></a><b id=\"resultview\">$finviews views</b> 

             </div> 
             <div id = \"border\"></div>"; 
         } 






       } 



        $totalPages = $pageNum; 
        $currentPage = $page; 
        $numPagesToShow = 10; 

        if($currentPage > $totalPages) { 
         $currentPage = $totalPages; 
        } 


        if($numPagesToShow >= $totalPages) { 
         $numMaxPageLeft = 1; 
         $numMaxPageRight = $totalPages; 
        } else { 
         $pagesToShow = ceil($numPagesToShow/2); 
         $numMaxPageLeft = $currentPage - $pagesToShow; 
         $numMaxPageRight = $currentPage + $pagesToShow; 

         if($numMaxPageLeft <= 0) { 
          $numMaxPageRight = $numMaxPageRight - $numMaxPageLeft +1; 
          $numMaxPageLeft = 1; 
         } elseif($numMaxPageRight >= $totalPages) { 
          $numMaxPageLeft -= ($numMaxPageRight - $totalPages); 
          $numMaxPageRight = $totalPages; 
         } 
        } 

        for ($i=$numMaxPageLeft; $i<=$numMaxPageRight; $i++) { 
         echo "<a id =\"pagenationlink\" href=\"searchresults.php?search=".$terms."&page=".$i."\">".$i."</a>"; 
        } 

如何，我只与它的两个结果，而不是与第八页上的两个相关结果11页显示一个网页？谢谢

Answer 1

请更新您的代码如下。
但尝试使用mysqli_ （）作为MySQL的（）的depricted

$cond = ""; 
if(!empty($_POST["search"])) 
{  
    $cond = " write your search condition " ; 
} 
$start = (($page-1)*5); 
$query = mysql_query("SELECT SQL_CALC_FOUND_ROWS * FROM posts where $cond LIMIT $start, 5"); 
$TotalDataQuery = mysql_query("SELECT FOUND_ROWS() tot;"); 
$rsVal = mysql_fetch_array($pagesQuery); 
$pagesQuery = $rsVal['tot']; 
$pageNum = ceil($pagesQuery/5); 

while ($row = mysql_fetch_array($query)) { 
//continue your code 
}