4
我正在学校实验室工作，我们被指示为计数程序创建一个递归互斥锁。我写了一些代码（这不起作用），但我认为这主要是因为我不明白使用递归互斥锁的真正想法。任何人都可以详细说明递归互斥锁应该做什么/看起来像什么？递归互斥锁后面的想法
一般注意：我没有要求答案，只是一些关于递归互斥锁应该做什么的澄清。
此外，如果任何人都好奇，这里是所需的代码。我正在编辑/执行的代码是recmutex.c。
recmutex.h
#include <pthread.h>
/*
* The recursive_mutex structure.
*/
struct recursive_mutex {
pthread_cond_t cond;
pthread_mutex_t mutex; //a non-recursive pthread mutex
pthread_t owner;
unsigned int count;
unsigned int wait_count;
};
typedef struct recursive_mutex recursive_mutex_t;
/* Initialize the recursive mutex object.
*Return a non-zero integer if errors occur.
*/
int recursive_mutex_init (recursive_mutex_t *mu);
/* Destroy the recursive mutex object.
*Return a non-zero integer if errors occur.
*/
int recursive_mutex_destroy (recursive_mutex_t *mu);
/* The recursive mutex object referenced by mu shall be
locked by calling pthread_mutex_lock(). When a thread
successfully acquires a mutex for the first time,
the lock count shall be set to one and successfully return.
Every time a thread relocks this mutex, the lock count
shall be incremented by one and return success immediately.
And any other calling thread can only wait on the conditional
variable until being waked up. Return a non-zero integer if errors occur.
*/
int recursive_mutex_lock (recursive_mutex_t *mu);
/* The recursive_mutex_unlock() function shall release the
recursive mutex object referenced by mu. Each time the owner
thread unlocks the mutex, the lock count shall be decremented by one.
When the lock count reaches zero, the mutex shall become available
for other threads to acquire. If a thread attempts to unlock a
mutex that it has not locked or a mutex which is unlocked,
an error shall be returned. Return a non-zero integer if errors occur.
*/
int recursive_mutex_unlock (recursive_mutex_t *mu);
recmutex.c：包含用于递归互斥
#include <stdio.h>
#include <pthread.h>
#include <errno.h>
#include "recmutex.h"
int recursive_mutex_init (recursive_mutex_t *mu){
int err;
err = pthread_mutex_init(&mu->mutex, NULL);
if(err != 0){
perror("pthread_mutex_init");
return -1;
}else{
return 0;
}
return 0;
}
int recursive_mutex_destroy (recursive_mutex_t *mu){
int err;
err = pthread_mutex_destroy(&mu->mutex);
if(err != 0){
perror("pthread_mutex_destroy");
return -1;
}else{
return 1;
}
return 0;
}
int recursive_mutex_lock (recursive_mutex_t *mu){
if(mutex_lock_count == 0){
pthread_mutex_lock(&mu->mutex);
mu->count++;
mu->owner = pthread_self();
printf("%s", mu->owner);
return 0;
}else if(mutex_lock_count > 0){
pthread_mutex_lock(&mu->mutex);
mu->count++;
mu->owner = pthread_self();
return 0;
}else{
perror("Counter decremented incorrectly");
return -1;
}
}
int recursive_mutex_unlock (recursive_mutex_t *mu){
if(mutex_lock_count <= 0){
printf("Nothing to unlock");
return -1;
}else{
mutex_lock_count--;
pthread_mutex_unlock(&mu->mutex);
return 0;
}
}
count_recursive.cc功能：上面提到的计数程序。使用recmutex函数。
#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <unistd.h>
#include <assert.h>
#include <string.h>
#include "recmutex.h"
//argument structure for the thread
typedef struct _arg_{
int n1;
int n2;
int ntimes;
}Arg;
int count; //global counter
recursive_mutex_t mutex; //the recursive mutex
void do_inc(int n){
int ret;
if(n == 0){
return;
}else{
int c;
ret = recursive_mutex_lock(&mutex);
assert(ret == 0);
c = count;
c = c + 1;
count = c;
do_inc(n - 1);
ret = recursive_mutex_unlock(&mutex);
assert(ret == 0);
}
}
/* Counter increment function. It will increase the counter by n1 * n2 * ntimes. */
void inc(void *arg){
Arg * a = (Arg *)arg;
for(int i = 0; i < a->n1; i++){
for(int j = 0; j < a->n2; j++){
do_inc(a->ntimes);
}
}
}
int isPositiveInteger (const char * s)
{
if (s == NULL || *s == '\0' || isspace(*s))
return 0;
char * p;
int ret = strtol (s, &p, 10);
if(*p == '\0' && ret > 0)
return 1;
else
return 0;
}
int test1(char **argv){
printf("==========================Test 1===========================\n");
int ret;
//Get the arguments from the command line.
int num_threads = atoi(argv[1]); //The number of threads to be created.
int n1 = atoi(argv[2]); //The outer loop count of the inc function.
int n2 = atoi(argv[3]); //The inner loop count of the inc function.
int ntimes = atoi(argv[4]); //The number of increments to be performed in the do_inc function.
pthread_t *th_pool = new pthread_t[num_threads];
pthread_attr_t attr;
pthread_attr_init(&attr);
pthread_attr_setscope(&attr, PTHREAD_SCOPE_SYSTEM);
ret = recursive_mutex_init(&mutex);
assert(ret == 0);
printf("Start Test. Final count should be %d\n", num_threads * n1 * n2 * ntimes);
// Create threads
for(int i = 0; i < num_threads; i++){
Arg *arg = (Arg *)malloc(sizeof(Arg));
arg->n1 = n1;
arg->n2 = n2;
arg->ntimes = ntimes;
ret = pthread_create(&(th_pool[i]), &attr, (void * (*)(void *)) inc, (void *)arg);
assert(ret == 0);
}
// Wait until threads are done
for(int i = 0; i < num_threads; i++){
ret = pthread_join(th_pool[i], NULL);
assert(ret == 0);
}
if (count != num_threads * n1 * n2 * ntimes) {
printf("\n****** Error. Final count is %d\n", count);
printf("****** It should be %d\n", num_threads * n1 * n2 * ntimes);
}
else {
printf("\n>>>>>> O.K. Final count is %d\n", count);
}
ret = recursive_mutex_destroy(&mutex);
assert(ret == 0);
delete [] th_pool;
return 0;
}
int foo(){
int ret;
printf("Function foo\n");
ret = recursive_mutex_unlock(&mutex);
assert(ret != 0);
return ret;
}
//test a thread call unlock without actually holding it.
int test2(){
int ret;
printf("\n==========================Test 2==========================\n");
pthread_t th;
pthread_attr_t attr;
pthread_attr_init(&attr);
pthread_attr_setscope(&attr, PTHREAD_SCOPE_SYSTEM);
ret = recursive_mutex_init(&mutex);
ret = pthread_create(&th, &attr, (void * (*)(void *))foo, NULL);
printf("Waiting for thread to finish\n");
ret = pthread_join(th, NULL);
assert(ret == 0);
return 0;
}
int main(int argc, char ** argv)
{
int ret;
count = 0;
if(argc != 5) {
printf("You must enter 4 arguments. \nUsage: ./count_recursive num_threads n1 n2 ntimes\n");
return -1;
}
if(isPositiveInteger(argv[1]) != 1 || isPositiveInteger(argv[2]) != 1 || isPositiveInteger(argv[3]) != 1 || isPositiveInteger(argv[4]) != 1){
printf("All the 4 arguments must be positive integers\n");
return -1;
}
test1(argv);
test2();
return 0;
}
是的。你可以使用'pthread_self（）'来获得你的线程ID –
^^这是现货。 – DevNull