2014-10-10 160 views
0

为了使脚本与PHP 5.5一起工作,我实际上从mysql-extension改为PDO。使用mysql扩展它可以正常工作,但是使用PDO会导致内存溢出。PDO导致内存溢出

这里是我使用的功能:

protected function getData($table) { 
    global $db; 
    $insert = ''; 
    $stmt = $db->query("-- " . __LINE__ . __FILE__ . " 
    SELECT * 
    FROM " . $table 
); 
    if ($result = $stmt->fetchAll()) { 
    $insert_into = "INSERT INTO `" . $table . "` VALUES ". PHP_EOL; 
    $insert = "/*!40000 ALTER TABLE `" . $table . "` DISABLE KEYS */;" . PHP_EOL; 
    $insert .= $insert_into; 
    $countRow = 0; 
    $split_tmp = ''; 
    foreach ($result as $row) { 
     $insert_tmp = "("; 
     foreach ($row as $data) { 
     if (!isset($data)) { 
      $insert_tmp .= 'NULL,'; 
     } else if ($data != '') { 
      $insert_tmp .= "'" . addslashes($data) . "',"; 
     } else { 
      $insert_tmp .= "'',"; 
     } 
     } 
     $insert_tmp = rtrim($insert_tmp, ',') . '),' . PHP_EOL; 
     $insert .= $insert_tmp; 
     if ($this->querySplit) { 
     $split_tmp .= $insert_tmp; 
     if ($countRow > $this->maxRow && strlen($split_tmp) > $this->maxLength) { 
      $countRow  = 0; 
      $split_tmp = ''; 
      $insert = rtrim($insert, PHP_EOL . ',') . ';' . PHP_EOL; 
      $insert .= "/*!40000 ALTER TABLE `" . $table . "` ENABLE KEYS */;" . PHP_EOL . PHP_EOL; 
      $insert .= "/*!40000 ALTER TABLE `" . $table . "` DISABLE KEYS */;" . PHP_EOL; 
      $insert .= $insert_into; 
     } 
     } 
     $countRow ++; 
    } 
    $insert = rtrim($insert, PHP_EOL . ',') . ';' . PHP_EOL; 
    $insert .= "/*!40000 ALTER TABLE `" . $table . "` ENABLE KEYS */;" . PHP_EOL. PHP_EOL; 
    } 
    return $insert; 
} 

即使切换到

$db->setAttribute(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY, false); 

没有帮助。

memory_limit设置为256MB。

+2

PDO不会造成内存溢出以下调整,您使用fetchall()的使用会导致内存溢出。一次取一行 – 2014-10-10 10:26:41

+1

当您调用'fetchAll()'时,您的整个结果集将被缓冲到内存中。诀窍是让MySQL尽可能减少结果集的数量,例如'SELECT field1,field2'而不是'SELECT *',特别是如果表中有大量的列。如果你拉下50000行......那么你肯定能看到这个问题吗? 此外,你为什么要在一个短的函数中调用PHP_EOL 12次?你是通过命令行调用它还是导出它? – iamgory 2014-10-10 11:29:49

+0

我需要所有的表字段,因为脚本要备份整个数据库。所以你的命名字段的解决方案不会改变任何东西。 – 2014-10-10 13:56:04

回答

0

使用fetchAll是一个非常糟糕的主意用大量的数据的时候,做使用fetch()

protected function getData($table) { 
    global $db; 
    $insert = ''; 
    $stmt = $db->query("-- " . __LINE__ . __FILE__ . " 
    SELECT * 
    FROM " . $table 
); 
    if ($result = $stmt->rowCount() > 0) { 
    $insert_into = "INSERT INTO `" . $table . "` VALUES ". PHP_EOL; 
    $insert = "/*!40000 ALTER TABLE `" . $table . "` DISABLE KEYS */;" . PHP_EOL; 
    $insert .= $insert_into; 
    $countRow = 0; 
    $split_tmp = ''; 
    while($row = $stmt->fetch()) { 
     $insert_tmp = "("; 
     foreach ($row as $data) { 
     if (!isset($data)) { 
      $insert_tmp .= 'NULL,'; 
     } else if ($data != '') { 
      $insert_tmp .= "'" . addslashes($data) . "',"; 
     } else { 
      $insert_tmp .= "'',"; 
     } 
     } 
     $insert_tmp = rtrim($insert_tmp, ',') . '),' . PHP_EOL; 
     $insert .= $insert_tmp; 
     if ($this->querySplit) { 
     $split_tmp .= $insert_tmp; 
     if ($countRow > $this->maxRow && strlen($split_tmp) > $this->maxLength) { 
      $countRow  = 0; 
      $split_tmp = ''; 
      $insert = rtrim($insert, PHP_EOL . ',') . ';' . PHP_EOL; 
      $insert .= "/*!40000 ALTER TABLE `" . $table . "` ENABLE KEYS */;" . PHP_EOL . PHP_EOL; 
      $insert .= "/*!40000 ALTER TABLE `" . $table . "` DISABLE KEYS */;" . PHP_EOL; 
      $insert .= $insert_into; 
     } 
     } 
     $countRow ++; 
    } 
    $insert = rtrim($insert, PHP_EOL . ',') . ';' . PHP_EOL; 
    $insert .= "/*!40000 ALTER TABLE `" . $table . "` ENABLE KEYS */;" . PHP_EOL. PHP_EOL; 
    } 
    return $insert; 
}