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我有一个API,我从以Base64角客户端发送一个形象,我为我的方法下一个代码创建:如何将所有属性设置为UploadedFile的Rails中4
if params[:profile][:picture]
picture_params = params[:profile][:picture]
#Create new Temporal File
temp_file = Tempfile.new("file_to_upload")
temp_file.binmode
temp_file.write(Base64.decode64(picture_params["body"]))
#Create a new uploaded file
uploaded_file = ActionDispatch::Http::UploadedFile.new(
:tempfile => temp_file,
:original_filename => picture_params[:name])
#After replace picture with the new uploaded file
params[:profile][:picture] = uploaded_file
Rails.logger.info "#{params[:profile]}"
end
@profile = @current_user.build_profile(profile_params)
if @profile.save
render "api/v1/profiles/show"
else
errors_array!(@profile.errors.full_messages, :unprocessable_entity)
end
时后,我打印我的PARAMS的信息是零
"picture"=>#<ActionDispatch::Http::UploadedFile:0x007f872daac5b0 @tempfile=#<Tempfile:/var/folders/nx/30024wp17ggfgw542lyzs4zw0000gn/T/file_to_upload20160225-14952-by947r>, @original_filename=nil, @content_type=nil, @headers=nil>}
当尝试创建我有下一个错误的配置文件后,我认为这是对以前的问题
NoMethodError (undefined method `gsub' for nil:NilClass):
app/controllers/api/v1/profiles_controller.rb:39:in `create'
我使用Rails中上传文件回形针宝石观看4.2.5.1