我的Python脚本通过urllib2打开一个文件;数据是这样的:关闭网站的CSV格式数据未被正确解析
"Charitable Donation: Contribution","012","","","","","","","","","","","","","","","","","","","",""
的Python脚本:
reader = csv.reader(data, delimiter=',', quotechar='"', quoting=csv.QUOTE_ALL)
for row in reader:
print row
输出是这样的:
['Charitable Donation: Contribution']
['', '']
['012']
['', '']
['']
['', '']
['']
['', '']
['']
['', '']
['']
['', '']
['']
['', '']
['']
['', '']
['']
['', '']
['']
['', '']
['']
我在做什么错?
它正在做你到底在问什么。你对“有用”的定义是什么? – 2012-01-04 20:28:45
'CSV'中的'C'代表'COMMA'代表'COMMA'作为你的分隔符,而不是''' – 2012-01-04 20:30:41
-1:显示的输出不是来自显示的代码 – 2012-01-04 21:00:29