MySQL独特的项目数量查询

Question

我有这个表上的MySQL。

CustomerName CustomerGroup hasPurchase 
Jerry  A    CAR 
Jerry  A    TOY 
Jerry  A    CAR 
Springer  B    DRINK 
Springer  B    CAR 
Springer  B    CAR 
Springer  B    DRINK 

我的预期结果：

CustomerName CustomerGroup totalPurchase uniquePurchase 
Jerry  A    3    2 
Springer  B    4    2 

totalPurchase是他买的全部项目。 uniquePurchase是他购买的不同类型的物品。

这是什么是正确的MySQL查询？ Thx寻求帮助。

Answer 1

SELECT DISTINCT CustomerName, 
       CustomerGroup, 
       COUNT(hasPurchase) as totalPurchase, 
       COUNT(DISTINCT hasPurchase) as uniquePurchase 
FROM XXX 
GROUP BY CustomerName, 
     CustomerGroup 

我没有在MySQL运行它一起，但我认为它应该工作。

Answer 2

假设客户名称和customerGroup是相同的每一行，使用count和count与distinct与group by

select customerName 
,customerGroup 
,count(hasPurchase) as totalPurchase 
,count(distinct hasPurchase) as uniquePurchase 
from your_table 
group by CustomerName,CustomerGroup 

Answer 3

您可以通过此

Count(hasPurchase)尝试组taotalPurchase

Count(Distinct hasPurchase)为uniquePurchase

SELECT customerName,customerGroup,count(hasPurchase) as totalPurchase,count(distinct hasPurchase) as uniquePurchase 
from table group by CustomerName;