MethodNotAllowedHttpException在岗位

Question

现在我学会建立一个像Facebook一样的Facebook。昨天，我可以发布状态，但一些修改后，状态发布简化版，工作

当我点击提交按钮 扔MethodNotAllowedHttpException

如何解决这一问题？ 尝试一些方法，但得到同样的结果

形式：

{{Form::open(array('url'=> 'postStatus','files'=>'true'))}} 
{{Form::textarea('status')}} 
{{Form::file('picture')}} 
{{Form::submit('Post')}} 
{{Form::close()}} 

路线：

Route::get('/', function() 
{ 
    if(Auth::check()){ 
     $post = Newsfeed::all(); 
     return View::make('frontend/home/index')->with('posts', $post->reverse()); 
    } 

    $months = []; 
    foreach (range(1, 12) as $month) { 
     $months[$month] = substr(strftime("%B", mktime(0, 0, 0, $month)), 0, 3); 
    } 
    $months = [''=>'Month'] + $months; 
    return View::make('frontend/register/index')->with('months', $months); 
}); 

Route::post('login', 'LoginController@validateLogin'); 
Route::get('logout', 'LoginController@doLogout'); 
Route::post('register', 'LoginController@validateRegister'); 

Route::post('upload', 'ProfileController@changePP'); 
Route::get('{username}', 'ProfileController@show'); 

Route::post('postStatus', 'HomeController@postStatus'); 
Route::get('deleteStatus/{postid}', 'HomeController@deleteStatus'); 
Route::get('unlike/{likeid}', 'HomeController@unlike'); 
Route::get('like/{postid}', 'HomeController@like'); 
Route::post('comment/{postid}', 'HomeController@postComment'); 
Route::get('deleteComment/{commentid}', 'HomeController@deleteComment'); 

的HomeController

public function postStatus() 
{ 
    try{ 
     $status = Input::get('status'); 
     $file = Input::file('picture'); 

     if($file !== '' || $status !=''){ 
      $post = new Newsfeed; 
      $post->userid = Auth::id(); 

      if($status !=''){ 
       $post->status = $status; 
      } 
      if($file != ''){ 
       $rules = array('file' => 'mimes:png,jpg,jpeg'); 
       $validator = Validator::make(array('file'=> $file), $rules); 
       if($validator->passes()){ 
        $destinationPath = 'images/upload'; 
        $filename = $file->getClientOriginalName(); 
        $file->move('public/'.$destinationPath, $filename); 
        $post->image = $destinationPath.'/'.$filename; 
       } 
      } 
      $post->save(); 
     } 
     return Redirect::to(''); 
    }catch(Exception $e){ 
     return Redirect::to(''); 
    } 
} 

ProfileController可

public function show($fullname) 
    { 
     $temp = explode('.',$fullname); 
     $owner = User::where('firstname', '=', $temp[0])->where('lastname', '=', $temp[1])->first(); 

     if($owner){ 
      return View::make('frontend/profile/index')->with('owner', $owner); 
     } 
     return View::make('frontend/profile/notfound'); 
    } 

Answer 1

您需要做的是将Route::get('{username}', 'ProfileController@show');作为最后一条路线。

发生了什么事是你的postStatus被作为用户名被拦截，并失败。

个人而言，我会改变你的用户名的路线是这样的

Route::get('/user/{username}', 'ProfileController@show'); 

否则你会得到奇怪的错误，这种类型包罗万象

Answer 2

添加“方法” =>“POST”在你的Form::open。

请参阅，如果这可以解决您的问题。