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我有下面的代码。基本上我有3个嵌套解析查询。一个是获得一些“追随者”,对于每个追随者,我得到了一些“想法”,并且对于每个想法我都希望得到这个想法创建者的名字(用户表中的用户)。嵌套的JavaScript查询解析
前两个嵌套查询可以工作,但当我尝试获取用户名称(创意者)时,最后一个嵌套查询不会按顺序执行。该查询被跳过,然后稍后在代码中执行。为什么会发生这种情况?
var iMax = 20;
var jMax = 10;
var IdeaList = new Array();
var IdeaListCounter = 0;
var myuser = Parse.User.current();
var Followers = new Parse.Query("Followers");
Followers.equalTo("Source_User",{__type: "Pointer",className: "_User",objectId: myuser.id});
Followers.find({
success: function(results) {
for (var i = 0; i < results.length; i++) {
var object = results[i];
var Ideas = new Parse.Query("Ideas");
Ideas.equalTo("objectId_User", {__type: "Pointer",className: "_User",objectId: object.get('Destination_User').id});
Ideas.find({
success: function(results2) {
for (i=0;i<iMax;i++) {
IdeaList[i]=new Array();
for (j=0;j<jMax;j++) {
IdeaList[i][j]=0;
}
}
for (var j = 0; j < results2.length; j++) {
var object2 = results2[j];
var ideausername2 = "";
IdeaListCounter++;
var ideausername = new Parse.Query("User");
ideausername.equalTo("objectId",object2.get('objectId_User').id);
ideausername.first({
success: function(ideausernameresult) {
ideausername2 = ideausernameresult.get("name");
}
});
IdeaList[IdeaListCounter,0] = object2.get('objectId_User').id + " " + ideausername2; //sourceuser
IdeaList[IdeaListCounter,1] = object2.get('IdeaText'); //text
IdeaList[IdeaListCounter,2] = object2.get('IdeaImage'); //image
IdeaList[IdeaListCounter,3] = object2.get('IdeaLikes'); //likes
IdeaList[IdeaListCounter,4] = object2.get('IdeaReport'); //reports