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说我们产生这样的字符串:如何将复杂的生成样式应用于jQuery?
background:#6356ff;
background:url(data:image/svg+xml;
base64,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);
background:linear-gradient(top,#6356ff 0%,#75b6ff 100%);
filter:progid:DXImageTransform.Microsoft.gradient(startColorstr='#6356ff',endColorstr='#75b6ff',GradientType=0);
,现在我们要这样复杂的样式应用到我们的文档HTML和身体。如何使用jQuery执行此类事情?
不应该引用实际值或什么?编辑:哦,等等......这是一个CSS定义?我相信OP问“生成的字符串”以应用为CSS ... – hayavuk 2012-02-25 22:21:22
我不认为这个答案。他们将CSS作为一个javascript字符串,我假设他们想知道如何通过javascript应用它。 – jfriend00 2012-02-25 22:23:16