2016-05-29 354 views
1

我刚刚在我的网页上发现了两个错误。我不是很习惯数据库,MySQL,所以我需要你来帮助我!警告:mysqli_connect():(28000/1045):访问被拒绝

警告:mysqli_connect():(1045分之28000):在/home/u467224226/public_html/galeria/api.php:拒绝访问用户u467224226_yjygu'@'10.1.2.19“(YES使用密码)第8行

警告:mysqli_error()预计参数1是在给定的/home/u467224226/public_html/galeria/api.php第8行

下面的代码的mysqli,布尔值。

<?php // connect to the database $user_name = ""; $password = ""; $database = ""; $host_name = "localhost"; 

$con = mysqli_connect($host_name ,$user_name ,$password,$database) or die("Error " .  mysqli_error($con)); //check connection 

echo "Connection opened"; 

mysql_close($con); ?> 

<?php require_once('include/config.inc.php');  header("Content-type: application/x-javascript"); 


      $connect = mysql_connect($CONFIG['dbserver'],$CONFIG['dbuser'],$CONFIG['dbpass'])  or die('Erro ao conectar ao servidor');  $connect_db = mysql_select_db($CONFIG['dbname'], $connect)  or die ('Erro ao conectar ao banco de dados'); 


       $resultado = mysql_query("SELECT * FROM `cpg_albums` ORDER BY `cpg_albums`.`aid` DESC LIMIT 0 , 4", $connect) 

        or die('Nenhum album encontrado com esta query'); 

        echo 'document.write(\''; 

        if(mysql_num_rows($resultado) == 0){ 
         echo 'Nenhum álbum cadastrado'; 
        } else { echo '<section id="ultimas_fotos"> '; 
         while($row = mysql_fetch_array($resultado)){ 
          echo ' '; 
           $album_id = $row['aid']; 
           $subresult = mysql_query("SELECT * FROM `cpg_pictures` where aid=$album_id order by pid DESC LIMIT 0, 20"); 

           if(mysql_num_rows($subresult) == 0){ 
            $album_img = "http://tisdalephotos.com/images/thumbs/thumb_nopic.png"; 
           } else { 
            while($subrow = mysql_fetch_array($subresult)){ 
             $album_img = "http://tisdalephotos.com/albums/".$subrow['filepath'].'thumb_'.$subrow['filename'] .$subrow['datebrowse']; 

            } 
           } 

           echo '<div id="ultalb"><a href="http://tisdalephotos.com/thumbnails.php?album='.$album_id.' "><img src="'.$album_img.'" alt="" /></a><div id="ultalbt"><a href="http://tisdalephotos.com/thumbnails.php?album='.$album_id.' ">+</a></div></div>'; 

          echo ''; 
         } 
        } 

echo '</tr></section>'; 
        echo '\');'; 
          ?> 
+0

你有什么想法,可能是什么? SO不只是一项调试服务。 –

+0

错误的登录信息(密码)? –

+0

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回答

0

假设您的密码正确。

您的用户是否拥有正确的权限?以root身份登录然后运行:

select Host, User from mysql.user; 

查看您的用户列出的内容。

如果它丢失,你可以运行:

CREATE USER 'u467224226_yjygu'@'%%' IDENTIFIED BY 'PASSWORD'; 
GRANT ALL PRIVILEGES ON * . * TO 'u467224226_yjygu'@'%%'; 
FLUSH PRIVILEGES;