2011-04-05 67 views
1

我有以下数据,我正在使用“http://commons.apache.org/jxpath/”我想直接读取坐标:[51.464426 -0.382974]这是lat,我怎么能读这个任何快速的例子,我搜索周围,发现还有另一个jsonpath以及jsonxpath将为我工作的任何快速解决方案?java jsonxpth解析json跳转到节点

{ 

    authenticationResultCode: "ValidCredentials" 
    brandLogoUri: http://dev.virtualearth.net/Branding/logo_powered_by.png 
    copyright: "Copyright © 2011 Microsoft and its suppliers. All rights reserved. This API cannot be accessed and the content and any results may not be used, reproduced or transmitted in any manner without express written permission from Microsoft Corporation." 
    - 
    resourceSets: [ 
     - 
     { 
      estimatedTotal: 1 
      - 
      resources: [ 
       - 
       { 
        __type: "Location:http://schemas.microsoft.com/search/local/ws/rest/v1" 
        - 
        bbox: [ 
         51.46056328242933 
         -0.39124021297987016 
         51.46828871757068 
         -0.3747077870201298 
        ] 
        name: "TW4 5AP, Hounslow, United Kingdom" 
        - 
        point: { 
         type: "Point" 
         - 
         coordinates: [ 
          51.464426 
          -0.382974 
         ] 
        } 
        - 
        address: { 
         adminDistrict: "England" 
         adminDistrict2: "Hounslow" 
         countryRegion: "United Kingdom" 
         formattedAddress: "TW4 5AP, Hounslow, United Kingdom" 
         postalCode: "TW4 5AP" 
        } 
        confidence: "High" 
        entityType: "Postcode1" 
       } 
      ] 
     } 
    ] 
    statusCode: 200 
    statusDescription: "OK" 
    traceId: "16c9b05027c4486fa3adab793cfdb97e|EWRM001665|02.00.82.2800|EWRMSNVM001812, EWRMSNVM001724" 

} 

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