嘿家伙我需要帮助为我的实验练习。我只需要通过这个问题..我唯一的问题,我需要确保将有一个例外,如果用户试图输入一个数字(特别是int)在一个字符串“但** 我使用java.util.Scanner
和读取输入的String
条件陈述如果用户输入整数而不是字符串
else if (userInput.hasNextInt())
我的问题只有
import java.util.*;
public class Quizbee{
public static void main (String args[]){
Scanner sc = new Scanner(System.in);
int score = 0;
String userInput;
String answerKey[] = {"A", "C", "B", "B", "C"}; //A, C,
String multichoice[][] = {{"A = Leonardo Da Vinci ", "B = Albert Einstein ","C = Stephen Hawking"}, //[0][0],[0][1],[0][2]
{"A = 9 ", "B = 8 ", "C = 7 "}, //[1][0],[1][1],[1][2]
{"A = Rodrigo Duterte ", "B = Ferdinand Marcos ", "C = Ninoy Aquino "}, //[2][0],[2][1],[2][2]
{"A = John F. Kennedy ","B = Abraham Lincoln ","C = Ronald Reagan "}, //[3][0],[3][1],[3][2]
{"A = Floyd Mayweather ","B = Manny Pacquaio ", "C = Muhammad Ali "}}; //[4][0],[4][1],[4][2]
{}
String arrQuestion[] = {"The Renaissance Man?", "prime number?","Longest-term serving Pres. of PH",
"1st US President to be assassinated", "Nicknamed \"The Greatest\" in the boxing history"};
for (int x = 0; x<arrQuestion.length; x++)
{
try
{
System.out.println("\n" + (x+1)+". " + arrQuestion[x]);
System.out.print(multichoice[x][0] + multichoice[x][1] + multichoice[x][2]+": ");
userInput = sc.nextLine();
if(userInput.equalsIgnoreCase(answerKey[x]))
{
System.out.println("Correct!");
score = score + 1;
}
else if(!userInput.equalsIgnoreCase(answerKey[x]))
{
if(userInput.isEmpty())
{
throw new NullPointerException();
}
else if(!userInput.equalsIgnoreCase("A") && !userInput.equalsIgnoreCase("B") && !userInput.equalsIgnoreCase("C"))
{
throw new OutOfRangeMisception();
}
else if(userInput.hasNextInt())
{
throw new InputMismatchException();
}
else
{
System.out.println("Wrong!");
score = score + 0;
}
}
}
catch(OutOfRangeMisception oor)
{
System.out.println(oor.getMessage());
}
catch(NullPointerException ex)
{
System.out.println("No answer. please try again.");
}
catch(InputMismatchException ex)
{
System.out.println("Wrong data type.");
}
}
System.out.println("\nYour score: " + score);
}
}
你的问题是什么?还是你要求我们为你做作业? – CraigR8806
欢迎,除了实验室要求,我没有看到具体的问题。即使有一个不好的英语(像我的),你可以专注于这个问题,并创建一个[mcve] – AxelH
而不是'userInput.hasNextInt()'我会建议'userInput.matches(“\\ d +”)''。它检查字符串是否包含数字。 –