如何在Python中运行后台计时器

Question

我正在制作一个数学游戏，用户有60秒的时间来回答尽可能多的问题。到目前为止，除了计时器应该倒数到0或者数到60以外，停止游戏之后，我就可以开始工作了。现在，我将计时器设置为time.clock（）以计数到60，而计时器小于此时，游戏将继续运行。但是，由于某些原因，time.clock（）并不像我预期的那样工作。我也尝试在同一时间运行两个while循环，这两个循环都不起作用。任何人都可以帮助我在这里？只需寻找一种让计时器在后台运行的方法。

这里是我的代码：

score = 0 
    timer = time.clock() 
    lives = 3 

    while timer < 60 and lives > 0: 
     if score >= 25: 
      x = random.randint(-100,100) 
      y = random.randint(-100,100) 
      answer = int(raw_input("What is %d + %d? " % (x,y))) 
      if answer == x + y: 
       print "Correct!" 
       score += 1 
      else: 
       print "Wrong!" 
       lives -= 1 
     elif score >= 20: 
      x = random.randint(-75,75) 
      y = random.randint(-75,75) 
      answer = int(raw_input("What is %d + %d? " % (x,y))) 
      if answer == x + y: 
       print "Correct!" 
       score += 1 
      else: 
       print "Wrong!" 
       lives -= 1 
     elif score >= 15: 
      x = random.randint(-50,50) 
      y = random.randint(-50,50) 
      answer = int(raw_input("What is %d + %d? " % (x,y))) 
      if answer == x + y: 
       print "Correct!" 
       score += 1 
      else: 
       print "Wrong!" 
       lives -= 1 
     elif score >= 10: 
      x = random.randint(-25,25) 
      y = random.randint(-25,25) 
      answer = int(raw_input("What is %d + %d? " % (x,y))) 
      if answer == x + y: 
       print "Correct!" 
       score += 1 
      else: 
       print "Wrong!" 
       lives -= 1 
     elif score >= 5: 
      x = random.randint(-10,10) 
      y = random.randint(-10,10) 
      answer = int(raw_input("What is %d + %d? " % (x,y))) 
      if answer == x + y: 
       print "Correct!" 
       score += 1 
      else: 
       print "Wrong!" 
       lives -= 1 
     elif score >= 0: 
      x = random.randint(-5,5) 
      y = random.randint(-5,5) 
      answer = int(raw_input("What is %d + %d? " % (x,y))) 
      if answer == x + y: 
       print "Correct!" 
       score += 1 
      else: 
       print "Wrong!" 
       lives -= 1 
    if lives == 0: 
     print "Oh no! You ran out of lives! Your score was %d." % score 
    elif timer == 60: 
     print "Time's up! Your score is %d." % score 
else: 
    print "Goodbye!" 

Answer 1

使用time.time()，它返回的信号出现时间（即自1970年1月1日，UNIX Time的秒数）。你可以把它比作一个开始时间来获得的秒数：用信号

start = time.time() 
while time.time() - start < 60: 
    # stuff 

您可以在任何时候（即使用户输入信息），你有一个计时器拔出你的代码，但它是更复杂一点。一种方法是使用信号库：

import signal 
def timeout_handler(signal, frame): 
    raise Exception('Time is up!') 
signal.signal(signal.SIGALRM, timeout_handler) 

这个定义引发了一个异常，并在发生超时时被调用的函数。现在，你可以把你的while循环在try catch块，并设置定时器：

signal.alarm.timeout(60) 
try: 
    while lives > 0 
     # stuff 
except: 
    # print score