对于学校我必须制作一个扫描器,它能够接受字符串输入并计算1“a”等元音的数量。我的问题是,当我输入一个字符串时,它不会经过循环,我可以连续输入和输入什么都不做。 (我使用BlueJ来编码)。谢谢你的帮助!Java代码没有处理输入
package VowelCounter;
/**
* Description:
* Author: Jack Cannon
* Date: 11/15/16
*/
import java.util.Scanner;
public class VowelCounter
{
public static void main(String [] args)
{
Scanner input = new Scanner(System.in);
//Prompt the user to enter a phrase
System.out.println("Type in a sentence.");
String phrase = input.nextLine();
//as long as the string isn't "quit",
//count the vowels in the string.
int length = phrase.length();
while(phrase != "quit")
{
int a = 0;
int e = 0;
int i = 0;
int o = 0;
int u = 0;
for(int c = 0; length < 1; length++)
{
char vowels = phrase.charAt(c);
if(vowels == 'a')
{
}
else if(vowels == 'e')
{
}
else if(vowels == 'i')
{
}
else if(vowels == 'o')
{
}
else if(vowels == 'u')
{
}
}
}
System.out.println("There are " + 'a' + "a's");
System.out.println("There are " + 'e' + "e's");
System.out.println("There are " + 'i' + "i's");
System.out.println("There are " + 'o' + "o's");
System.out.println("There are " + 'u' + "u's");
//print out the count of the vowels for this string.
//prompt the user for another phrase.
}
}
你永远只要求输入一次......也使用字符串的equals方法Java中 –
比较字符串时是否有您使用的环路长度<1的原因吗?这不会遍历整个字符数。也可以看看使用开关盒 –