命名文件带有图案

Question

Python的初学者在这里。

我有数百命名为（按顺序）图像文件的目录：

002_IMG_001，002_IMG_002，002_IMG_003，002_IMG_N

现在，我想重新命名这些图像，使得五在一排文件有“N”从1：5，即每一套连续五个图像得到N，1至5我还要数“N”之前，粘另一个字符串。此字符串将跟踪这一集N个图像，e.g，IMG_001_1，IMG_001_2，.. IMG_001_N，IMG_002_1，IMG_002_2，的...... IMG_00X_N。

在Mac上的Python 2.7.10伪代码如下所示：

import os 

myDir = "/Users/path/to/dir/" 
fileList = os.listdir(myDir) 

for filename in fileList : 
    #split the images into sets of five each 
    newFile = 'IMG_' + '00' + X + '_' + N 
     #loop through images and rename 
      os.rename(fileName, newFile) 

我想我需要内部条件循环，财产以后这样的：

if int(filename[9:12]) % 5 == 0 

但是这将意味着，我必须为1到5创建五个单独的条件，这看起来不正确。任何暗示将不胜感激？

编辑：目前尚不清楚一些是需要什么样的输出。我找了一个函数来得到这样的最终文件名：IMG_001_1，IMG_001_2，... IMG_001_5，IMG_002_1，IMG_002_2，... IMG_002_5，...

Answer 1

我认为这应该工作：

my_list = ["002_IMG_001", "002_IMG_002", "002_IMG_003", "002_IMG_004", "002_IMG_005", 
     "002_IMG_006", "002_IMG_007", "002_IMG_008", "002_IMG_009", "002_IMG_0010", 
     "002_IMG_011", "002_IMG_012", "002_IMG_013", "002_IMG_014", "002_IMG_015", 
     "002_IMG_016", "002_IMG_017", "002_IMG_018", "002_IMG_019", "002_IMG_0020", 
     ] 
fileList.sort() 

print("Original list:\n") 
print(fileList) 

new_list = [] 

for index, old_file_name in enumerate(fileList): 
    group, subgroup = divmod(index,5) 
    group, subgroup = group + 1, subgroup + 1 
    new_file_name = "IMG_{0:03d}_{1}".format(group, subgroup) 
    new_list.append(new_file_name) 

    os.rename(old_file_name, new_file_name) 

print("\nNew list:\n") 
print (new_list) 

这里是输出：

Original list: 

['002_IMG_001', '002_IMG_002', '002_IMG_003', '002_IMG_004', '002_IMG_005', 
'002_IMG_006', '002_IMG_007', '002_IMG_008', '002_IMG_009', '002_IMG_0010', 
'002_IMG_011', '002_IMG_012', '002_IMG_013', '002_IMG_014', '002_IMG_015', 
'002_IMG_016', '002_IMG_017', '002_IMG_018', '002_IMG_019', '002_IMG_0020'] 

New list: 

['IMG_001_1', 'IMG_001_2', 'IMG_001_3', 'IMG_001_4', 'IMG_001_5', 
'IMG_002_1', 'IMG_002_2', 'IMG_002_3', 'IMG_002_4', 'IMG_002_5', 
'IMG_003_1', 'IMG_003_2', 'IMG_003_3', 'IMG_003_4', 'IMG_003_5', 
'IMG_004_1', 'IMG_004_2', 'IMG_004_3', 'IMG_004_4', 'IMG_004_5']