0
...表名是参数。我在这里找到了解决方案:unable to store return value from execute statement in mysql 但它不适合我。这是我的测试:我在准备好的陈述中挣扎,其中
SET @v_sourceTableSize = 0;
SET @parameter_sourceTable = category;
SET @v_query = CONCAT("SELECT COUNT(*) INTO ",@v_sourceTableSize," FROM ",@parameter_sourceTable);
类别是在我的分贝表。当我运行这个时,没有任何反应。没有错误,没有。有没有办法让它工作?自上午以来我一直在寻找解决方案!
编辑
我把报价和现在,它正在与“类别”,但是我原来的程序没有。请看看:
DROP PROCEDURE IF EXISTS insert_categories;
DELIMITER $$
CREATE PROCEDURE insert_categories(
IN parameter_sourceTableIdColumnName INTEGER,
IN parameter_sourceTable VARCHAR(25),
IN parameter_sourceColumn VARCHAR(25),
IN parameter_destinationParentCategoryID INTEGER)
MODIFIES SQL DATA
BEGIN
DECLARE v_parameterSourceTable VARCHAR(25) DEFAULT "";
DECLARE v_sourceTableSize INTEGER;
DECLARE v_counter INTEGER DEFAULT 0;
DECLARE v_query VARCHAR(100) DEFAULT "";
DECLARE v_recordName VARCHAR(25) DEFAULT "";
SET v_parameterSourceTable = parameter_sourceTable;
SET v_query = CONCAT("SELECT COUNT(*) INTO ",v_sourceTableSize," FROM ",v_parameterSourceTable);
PREPARE stmt FROM v_query;
EXECUTE stmt;
SELECT v_sourceTableSize;
#SET v_sourceTableSize := (SELECT COUNT(*) FROM parameter_sourceTable);
SET v_sourceTableSize = v_sourceTableSize + 1;
WHILE v_counter < v_sourceTableSize DO
SET v_counter = v_counter + 1;
SET v_recordName = (SELECT parameter_sourceColumn
FROM v_parameterSourceTable
WHERE parameter_sourceTableIdColumnName = v_counter);
CALL insertCategory(v_recordName, parameter_destinationParentCategoryID);
END WHILE;
END $$
DELIMITER ;
我得到这个错误:
1064 - 你在你的SQL语法错误;检查与您的MariaDB服务器版本相对应的手册,以找到在'v_query; EXECUTE stmt; SELECT v_sourceTableSize; SET v_sourceTa”在行17