PHP添加文件路径到数据库

Question

我已经把这个脚本放在一起加载从我上传的文件到数据库的文件路径。但它似乎并不奏效。请任何建议都很好。它基本上是一个允许多个文件上传的简单表单。我需要通过文件路径将此信息传递给数据库以备后用。 我得到的 输出警告这是一个简单的测试来检查变量实际上是贴

这里是回声$ SQL;

INSERT INTO mediamanagement (`Project_Name`, `Assigned_To`, `Assign_Date`, `Check_Date`, `Due_Date`) VALUES ("fvfg df fdh bdfgb", "Ramon", "2013-04-01", "2013-04-18", "2013-04-30", Error:You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 13 
     Error:You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 13 

继承人的PHP：

<?php 
mysql_connect("MySQLB15.wer.com","york","usa12") or die ('Error:' .mysql_error()); 
//database connection 
    mysql_select_db("mediamanagement"); 

$project = $_POST['project']; 
$assignto = $_POST['assignto']; 
$asdate = $_POST['asdate']; 

$chdate = $_POST['chdate']; 
$ddate = $_POST['ddate']; 



$errors = array(); 
$files = array(); 
foreach ($_FILES['files'] as $k=>$image) { 

    // handle upload errors 
    if ($image['error'] != 0 && $image['error'] != 4) {   
     switch ($image['error']) { 
      case '1': 
      case '2': 
       $err = 'The uploaded file exceeds the maximum file size.'; 
       break;     
      case '3': 
       $err = 'The upload was inturupted, transfer failed.'; 
       break; 
      case '6': 
      case '7': 
      case '8': 
       $err = 'Server error. Please try again later.'; 
       break; 
     } 
     // record error and move on 
     $errors[] = array('files'=>$k, 'error'=>$err); 
     continue; 
    } elseif ($image['error'] == 4) { 
     // error 4 means no image was sent 
     continue; 
    } 

    // determine the extension 
    $ext = explode('.', $image['name']); 
    if (count($ext) != 2) { 
     $errors[] = array('files'=>$k, 'error'=>'Could not determine file extension.'); 
     continue; 
    } else { 
     switch ($ext[1]) { 
      case 'jpg': 
      case 'jpeg': 
      case 'gif': 
      case 'png': 
      case 'pdf': 
      case 'psd': 
      case 'ai': 
      case 'pdf': 


       break; 
      default: 
       $errors[] = array('files'=>$k, 'error'=>'Unsupported file extension.'); 
       continue; 
       break; 
     } 
    } 

    // make a random-ish filename 
    $filename = time().uniqid(rand(), true) . '.' . $ext[1]; 
    $path = 'uploads/'.$filename; // upload directory path is set 

    move_uploaded_file($image['tmp_name'], $path);  // upload the file to the server 
    // this is a bad idea right here! Use 775 at least, if possible 
    chmod($path,0775); 
    $files[] = array('name'=>$filename, 'path'=>$path); 
} 

// now loop the $files array and put the paths into the database 

// you also should do something with the errors listed in $errors 
// start building up the SQL query, start with 
// some fields that are straightforward 


$sql = ' 
    INSERT INTO mediamanagement (
     `Project_Name`, 
     `Assigned_To`, 
     `Assign_Date`, 
     `Check_Date`, 
     `Due_Date`'; 

// now loop the list of files (5 only), 
// add each needed field 

for ($i=1; $i < count($files) && $i < 5; $i++) { 
    $sql .= '`files'.$i.'`,'; 
} 

// build out the rest of the query, add values 
// for the straightforward fields 
$sql .= ' 

) VALUES (
    "'.$project.'", 
    "'.$assignto.'", 
    "'.$asdate.'", 
    "'.$chdate.'", 
    "'.$ddate.'", 
'; 



// loop the files 
$ct = 1; 
foreach ($files as $f) { 
    $sql .= '"'.$f['name'].'",'; 
    // only allow 5 files 
    if ($ct == 5) 
     break; 
    $ct++; 
} 
')'; 




mysql_query($sql) or die ('Error:' .mysql_error());; 





?> 

<?php 
echo("<p><span>Project Name:</span> ".$_POST['project']."</p>"); 
echo("<p><span>assign to:</span> ".$_POST['assignto']."</p>"); 
echo("<p><span>Assign Date:</span> ".$_POST['asdate']."</p>"); 
echo("<p><span>Check Date:</span> ".$_POST['chdate']."</p>"); 
echo("<p><span>Due Date:</span> ".$_POST['ddate']."</p>"); 



?> 

Answer 1

让你的SQL查询的转储，并张贴 BTW。我不认为，你知道你做什么......，只是复制和过去由其他

Answer 2

麻烦有

for ($i=1; $i < count($files) && $i < 5; $i++) { 
    $sql .= '`files'.$i.'`,'; 
} 
than 
) VALUES (

and we got ',) VALUE(