模板参数无效

Question

我试图获取模板挂，并具有以下代码：

town.h

#ifndef TOWN_H 
#define TOWN_H 

namespace segregation { 
    template <typename Pos, typename Resident, template <typename> class Container> 
    class Town { 
    public: 
     Town(); 
     virtual ~Town(); 
     virtual Resident getResident(Pos address); 
     virtual void move(const Pos& from, const Pos& to); 
     virtual Container<Resident> getNeighbours(const Pos address); 
    }; 
} 


#endif /* TOWN_H */ 

和

flat_town.h

#ifndef FLAT_TOWN_H 
#define FLAT_TOWN_H 
#include "town.h" 
#include <array> 
#include <forward_list> 
#include <utility> 
namespace segregation { 

    template<int x, int y, class R> 
    using TownMap = std::array<std::array<R, y>, x>; 

    template <typename R> 
    using Neighbourhood = std::forward_list<R>; 

    using Pos = std::pair<int, int>; 

    template <int x, int y, class Resident> 
    class FlatTown: public Town<Pos, Resident, Neighbourhood<typename Resident>> { 
    private: 
     TownMap<x, y, Resident> m_townMap; 
     int m_neighbourhood_size; 

    public: 
     FlatTown(TownMap<x, y, Resident> t_townMap, int t_neighbourhood_size) : 
      m_townMap(t_townMap), m_neighbourhood_size(t_neighbourhood_size) {}; 

     Resident getResident(const Pos & address); 

     void move(const Pos & from, const Pos & to); 

     Neighbourhood<Resident> getNeighbours(const Pos & address); 

     virtual ~FlatTown(); 
    }; 
} 

#endif /* FLAT_TOWN_H */ 

我目前还没有一个IDE，所以我通过运行

$ g++ flat_town.h 

产生以下错误验证正确性：

flat_town.h:18:76: error: template argument 1 is invalid 
    class FlatTown: public Town<Pos, Resident, Neighbourhood<typename Resident>> { 
                      ^~ 
flat_town.h:18:45: error: template argument 3 is invalid 
    class FlatTown: public Town<Pos, Resident, Neighbourhood<typename Resident>> { 
              ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

我觉得这些更高级的模板非常不确定和所有帮助表示赞赏。

问候，托比亚斯

Answer 1

您指定模板模板参数不正确。只需指定模板的名称，即

class FlatTown: public Town<Pos, Resident, Neighbourhood> {