计算平均成绩不会成功

Question

我必须计算某人在Python中的平均成绩。我收到一个输入文件，并结合这一点，我必须计算每个人的平均等级。我尝试了很多，但我只有第一人的平均成绩。有人可以帮助我吗？

输入文件是以下各项：

Tom Bombadil__________6.5 5.5 4.5 
Dain IJzervoet________6.7 7.2 7.7 
Thorin Eikenschild____6.8 7.8 7.3 
Meriadoc Brandebok____1.0 5.0 7.7 
Sam Gewissies_________2.3 4.5 6.7 

的输出是如下：

Tom Bombadilhas an average grade of 5.5 
Dain IJzervoethas an average grade of 5.5 
Thorin Eikenschildhas an average grade of 5.5 
Meriadoc Brandebokhas an average grade of 5.5 
Sam Gewissieshas an average grade of 5.5 

我用这个代码：

def names(lines): 
    for i in lines: 
     invoer_split = i.split("_") 
     first_name = invoer_split[0] 
     print first_name + "has an average grade of %.1f" %(average_grade(names)) 

def average_grade(names): 
    for i in lines: 
     grades_split = i.split("_") 
     grades = grades_split[-1] 
     grades_float = map(float,grades.split()) 
     grades_average = sum(grades_float)/3 
     return grades_average 

grades_file = open('grades1+2.in') 
lines = grades_file.readlines() 

names(lines) 
average_grade(names) 

Answer 1

代替处理名和等级分开做，同时做。我们将把输入变成一个将字符串映射到浮点的字典。

with open('filename') as f: 
    grades_dict = {} 
    for line in f: 
     name, *underscores, grades = line.split('_') #I forget when this syntax became a thing. You might have to assign these separately 
     grades = list(map(float, grades.split())) 
     grades_dict[name] = sum(grades)/len(grades) 

for name, grade in grades_dict.items(): 
    print('{0} has an avergae grade of {1}'.format(name, grade)) 

Answer 2

作为Patrick解决方案的替代方案，您可以使用它。

def average_grade(grades_string): 
    # split on whitespace 
    grades = grades_string.split(' ') 
    # convert to floats (we convert map to list for python3 compatibility) 
    grades = list(map(float, grades)) 
    # return the average 
    return sum(grades)/len(grades) 

# This is the same as "lines = open()", but closes the file after we finish 
with open('grades1+2.txt') as lines: 
    # Start iterating 
    for line in lines: 
     # When we split by underscores, we will get three parts: 
     # the name; the empty string (where underscores were); the grades. 
     # We can do that in one assignment 
     name, ignore_this, grades_str = line.split('_') 
     # now print the result (converting average to string) 
     print(name + ' has an average of ' + str(average_score(grades_str)))