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我有一个包含用户注册表单的弹出窗口。用户点击订阅后，我想要删除表单并显示一条感谢信息。所有这些都需要使用php来运行。表单提交后，使用PHP替换消息内容
以下是我到目前为止的内容，但弹出窗口并未保持不变，当再次单击订阅按钮时，它会显示表单验证错误，因为'subscribeSubmit'变量已设置。
那么，如何保持弹出窗口打开并用欢迎消息替换窗体？
请大家帮忙，谢谢！
<?php
if(isset($_POST['subscribeSubmit'])){
unset($error); //errasing error variable
//**************finding errors in form*******************
if(strlen($_POST['Fname']) <= 0) {$error[] = "Your name is required.";}
if(!eregi("^[[:alnum:]][a-z0-9_.-]*@[a-z0-9.-]+\.[a-z]{2,6}$", stripslashes(trim($_POST['emailPopin'])))) {$error[] = "Your e-mail address is not valid.";}
if(strlen($_POST['emailPopin']) <= 5) {$error[] = "You have to enter at least one e-mail to subscribe.";}
if(strlen($_POST['industry']) <= 0) {$error[] = "Your industry is required.";}
if(strlen($_POST['country']) <= 0) {$error[] = "Your country is required.";}
if(strlen($_POST['zip']) <= 0) {$error[] = "Your zip is required.";}
//************if there is an error**********
if(sizeof($error) > 0)
{
report_errors($error);
subscribe_form();
}
//**********if there is no error, we can subscribe them******
else
{
//**********Reduce First Name to 30 characters and replace special characters******
$name = substr($_POST['Fname'], 0, 30);
//***** Replaces special characters ******
$name = special_letters($name);
//**********write to data file******
//Left out on purpose
//**********Display thank you message******
echo '<p>Thanks for signing up!<br/><a href="#" onClick="window.location.href=window.location.href">Click here to sign up friends.</a></p>';
}
}
else
{
$Fname = $_POST["Fname"];
$email = $_POST["emailPopin"];
$leader = $_POST["radiobuttonTeamLeader"];
$industry = $_POST["industry"];
$country = $_POST["country"];
$zip = $_POST["zip"];
echo '<form action="" method="post" enctype="multipart/form-data" style="background:#efefef;">';
echo '<div style="text-align:left;background:#efefef;padding-bottom:4px;"><p style="line-height:20px; font-size:12px;">Fill in the form below to signup for our free daily newsletter. All fields are Necessary.(<span class="required">*</span>).</p><table id="popupSubscribe-form">';
echo '<tr><td class="label"><label for="name">First Name: <span class="required">*</span></label></td><td><input type="text" name="f_name" size="30" value=""></td></tr>';
echo '<tr><td class="label"><label for="email">Email: <span class="required">*</span></label></td><td><input type="text" size="30" id="emailPopin" value=""></td></tr>';
echo '<tr><td class="label"><label for="email">I Lead A Team: <span class="required">*</span></label></td>';
echo '<td><table><tr><td><input type="radio" value="yes" name="radiobuttonTeamLeader" style="width:15px;"><strong style="margin: 0 15px 0 5px;">Yes</strong></td>';
echo '<td><input type="radio" value="no" name="radiobuttonTeamLeader" style="width:15px;"><strong style="margin: 0 15px 0 5px;">No</strong></td></tr></table></td>';
echo '<tr><td class="label"><label for="industry">Industry: <span class="required">*</span></label></td><td><input type="text" name="industry" size="30" value=""></td></tr>';
echo '<tr><td class="label"><label for="country">Country <span class="required">*</span></label></td>';
echo '<td><select size="1" class="countryDropDown" name="country">';
echo '<option value="us" selected="selected">United States</option>';
echo '<option value="ca" >Canada</option>';
echo '</select></td></tr>';
echo '<tr><td class="label"><label for="email">Zip Code: <span class="required">*</span></label></td><td><input type="text" name="zip" size="30" value=""></td></tr>';
echo '<tr><td></td><td><input type="submit" id="subscribeSubmit" value="" name="subscribeSubmit"/></td></tr></table></div>';
echo '</form>';
}
}
你说：'再次点击订阅按钮时，它会显示表单验证错误。所以出现有效的错误？或者你是说没有实际的错误，错误部分出现不正确？ – 2010-01-08 21:33:38
不，提交表单时没有有效的错误。 所以会发生什么。我填写表格，点击订阅，弹出消失，而不是显示谢谢你的消息。然后，我点击'点击此处订阅'按钮，弹出窗体并显示验证错误。 这是因为设置了isset（$ _ POST ['subscribeSubmit']）而引起的。 我只是不知道如何解决它。 – Joe 2010-01-08 21:46:52
这不是您需要更改的代码。我们需要看到'subscribe_form（）'函数。它似乎是关闭你的弹出窗口。 – mattbasta 2010-01-10 23:25:00