我需要公式列名“FEBRUARY”

表1

   +------+-------+ 
       | JANUARY | 
       +------+-------+ 
+----+----------+------+-------+ 
| ID | NAME  |COUNT | PRICE | 
+----+----------+------+-------+ 
| 1 | ALFRED | 11 | 150 | 
| 2 | ARIS | 22 | 120 | 
| 3 | JOHN | 33 | 170 | 
| 4 | CHRIS | 22 | 190 | 
| 5 | JOE  | 55 | 120 | 
| 6 | ACE  | 11 | 200 | 
+----+----------+------+-------+

SHEET2

+----+----------+------+-------+ 
| ID | NAME  |COUNT | PRICE | 
+----+----------+------+-------+ 
| 1 | CHRIS | 13 | 123 | 
| 2 | ACE  | 26 | 165 | 
| 3 | JOE  | 39 | 178 | 
| 4 | ALFRED | 21 | 198 | 
| 5 | JOHN | 58 | 112 | 
| 6 | ARIS | 11 | 200 | 
+----+----------+------+-------+

的结果应该是这样的在Sheet1：

   +------+-------++------+-------+ 
       | JANUARY | FEBRUARY | 
       +------+-------++------+-------+ 
+----+----------+------+-------++-------+-------+ 
| ID | NAME  |COUNT | PRICE || COUNT | PRICE | 
+----+----------+------+-------++-------+-------+ 
| 1 | ALFRED | 11 | 150 || 21 | 198 |  
| 2 | ARIS | 22 | 120 || 11 | 200 |  
| 3 | JOHN | 33 | 170 || 58 | 112 |  
| 4 | CHRIS | 22 | 190 || 13 | 123 |  
| 5 | JOE  | 55 | 120 || 39 | 178 |  
| 6 | ACE  | 11 | 200 || 26 | 165 |   
+----+----------+------+-------++-------+-------+

我需要在列名公式 “二月” 。此公式将找到其匹配在片2

来源

2014-11-24 Derfla Smith

尝试此

SELECT T2.ID_ENTRY, T1.TAG, T1.TAG2, T2.Name, T2.LastName, T2.Age, T2.Tel 
FROM Table1 T1 
INNER JOIN Table2 T2 
ON T1.ID = T2.ID 
GROUP BY T2.ID_ENTRY, T1.TAG, T1.TAG2, T2.Name, T2.LastName, T2.Age, T2.Tel 
HAVING Count(T2.ID_ENTRY) > 1

来源

2014-11-24 00:46:30

列“Table2.ID_ENTRY”在选择列表中无效。 - 得到这个错误 – 2014-11-24 02:09:16

你有没有检查过它是否在组中 - 就像我在上面的回答中显示的那样？我确实有一个小的语法错误 - 现在已修复。 – 2014-11-24 02:10:58

谢谢，我明白了。还有一个问题可以计算2个字段为例（T2.Name＆T2.LastName） – 2014-11-24 03:08:22

BUILD样本数据

create table table1(
    id int, 
    id_entry varchar(10), 
    tag int, 
    tag2 int 
) 
create table table2(
    id int, 
    name varchar(50), 
    lastname varchar(50), 
    age int, 
    tel int 
) 
insert into table1 
select 1, 'A1', 11, 12 union all 
select 2, 'C2', 22, 13 union all 
select 3, 'S5', 33, 14 union all 
select 4, 'C2', 22, 13 union all 
select 5, 'B6', 55, 16 union all 
select 6, 'A1', 11, 12 

insert into table2 
select 1, 'ALFRED', 'DAVE', 21, 555 union all 
select 2, 'FRED', 'SMITH', 22, 666 union all 
select 3, 'MANNY', 'PAC', 23, 777 union all 
select 4, 'FRED', 'DAVE', 22, 666 union all 
select 5, 'JOHN', 'SMITH', 25, 999 union all 
select 6, 'ALFRED', 'DAVE', 21, 555

SOLUTION

;with cte as(
    select 
     t1.id_entry, 
     t1.tag, 
     t1.tag2, 
     t2.name, 
     t2.lastname, 
     t2.age, 
     t2.tel, 
     cc = count(*) over(partition by t1.id_entry), 
     rn = row_number() over(partition by t1.id_entry order by t2.lastname desc) 
    from table1 t1 
    inner join table2 t2 
     on t2.id = t1.id 
) 
select 
    id_entry, 
    tag, 
    tag2, 
    name, 
    lastname, 
    age, 
    tel 
from cte 
where 
    cc > 1 
    and rn = 1

d因为它不是在聚合函数或GROUP BY子句中包含ROP样本数据

drop table table1 
drop table table2

来源

2014-11-24 00:52:12

我需要公式列名“FEBRUARY”

回答

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