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我很难将这个AJAX代码实现到我的表单中，以便页面不需要重新加载，但仍然会执行服务器端验证。我是AJAX和PHP的新手，所以我正在处理一些表单模板，但是我一直在研究这个问题好几个小时，但我无法弄清楚它为什么不起作用。任何帮助，将不胜感激。将表单数据发送到PHP服务器进行验证的Ajax代码
这里是HTML代码的一部分：
<div id="popupContact">
<form id="formElem" name="formElem" action="" method="post">
<fieldset class="step">
<legend>Personal Details</legend>
<p>
<label for="firstname">First Name</label><em>*</em>
<input id="firstname" name="firstname" />
</p>
<p>
<label for="lastname">Last Name</label><em>*</em>
<input id="lastname" name="lastname" />
</p>
<p>* fields are required</p>
</fieldset>
<fieldset class="step">
<legend>Confirm</legend>
<p>Before you submit your information, please ensure that each step
below has this <img src="../img/global/checked.png" alt="Complete" >
above them. If there is a step that has this
<img src="../img/global/error.png" alt="Error" >, please click on that tab
and review the information to ensure it is correct and complete. Thank you.</p>
<p>
<label for="human">Please Type: "Something"</label><em>*</em>
<input id="human" name="human" />
</p>
<p class="submit">
<button id="registerButton" type="submit">Submit</button>
</p>
</fieldset>
</form>
</div>
这里的JavaScript代码：
$(function() {
var form = $("#formElem");
var fname = $("#firstname");
var lname = $("#lastname");
var address = $("#streetaddress");
var city = $("#city");
var state = $("#state");
var phone = $('#phone');
var email = $('#email');
var insurance = $('#insurance');
var license = $('#license');
var human = $('#human');
$('#registerButton').bind('click',function(){
if($('#formElem').data('errors')){
alert('Please correct the errors in the Form');
return false;
}
else {
var dataString = 'fname='+$('#firstname').val()+'&lname='+$('#lastname').val()+'&address='+$('#streetaddress'.val())+'&city='+$('#city')+'&state='+$('#state').val()+'&phone='+$('#phone').val()+'&email='+$('#email').val()+'&insurance='+$('#insurance').val()+'&license='+$('#license').val()+'&human='+$('#human').val();
$.ajax({
type: "POST",
url: "js/validation.php",
data: dataString,
async: false,
success: function() {
$('#popupContact').html("<div id='message'></div>");
$('#message').html("<h2>Inquiry Submitted!</h2>")
.append("<p>We will be in touch soon.</p>")
.hide()
.fadeIn(1500, function() {
$('#message').append("<img id='checkmark' src='..img/global/check.png' />");
});
}
});
return false;
}
});
而这里的PHP代码：
<?php
if(isset($_POST['email'])) {
$email_to = "[email protected]";
$email_subject = "Inquiry";
function died($error) {
// your error code can go here
echo "We are very sorry, but there were error(s) found with the form you submitted. ";
echo "These errors appear below.<br /><br />";
echo $error."<br /><br />";
echo "Please go back and fix these errors.<br /><br />";
die();
}
// validation expected data exists
if(!isset($_POST['firstname']) ||
!isset($_POST['lastname']) ||
!isset($_POST['email']) ||
!isset($_POST['phone']) ||
!isset($_POST['streetaddress']) ||
!isset($_POST['city']) ||
!isset($_POST['state']) ||
!isset($_POST['insurance']) ||
!isset($_POST['license']) ||
!isset($_POST['human'])){
died('We are sorry, but there appears to be a problem with the form you submitted.');
}
$firstname = $_POST['firstname']; // required
$lastname = $_POST['lastname']; // required
$emailfrom = $_POST['email']; // required
$phone = $_POST['phone']; // required
$address = $_POST['streetaddress']; //required
$city = $_POST['city']; //required
$state = $_POST['state']; //required
$insurance = $_POST['insurance']; //required
$license = $_POST['license']; //required
$human = $_POST['human']; //required
$error_message = "";
$email_exp = '/^[a-zA-Z0-9]+[a-zA-Z0-9_.-]+[a-zA-Z0-9_-][email protected][a-zA-Z0-9]+[a-zA-Z0-9.-]+[a-zA-Z0-9]+.[a-z]{2,4}$/';
if(!preg_match($email_exp,$emailfrom)) {
$error_message .= 'The Email Address you entered does not appear to be valid.<br />';
}
$email_message = "Form details below.\n\n";
function clean_string($string) {
$bad = array("content-type","bcc:","to:","cc:","href");
return str_replace($bad,"",$string);
}
$email_message .= "First Name: ".clean_string($firstname)."\n";
$email_message .= "Last Name: ".clean_string($lastname)."\n";
$email_message .= "Email: ".clean_string($emailfrom)."\n";
$email_message .= "Telephone: ".clean_string($phone)."\n";
$email_message .= "Address: \n".clean_string($address)."\n";
$email_message .= "".clean_string($city).", ";
$email_message .= "".clean_string($state)."\n";
$email_message .= "Have Insurance: ".clean_string($insurance)."\n";
$email_message .= "Have License: ".clean_string($license)."\n";
// create email headers
$headers = 'From: '.$email_from."\r\n".
'Reply-To: '.$email_from."\r\n" .
'X-Mailer: PHP/' . phpversion();
@mail($email_to, $email_subject, $email_message, $headers);
?>
<!-- include your own success html here -->
Thank you for contacting us. We will be in touch with you very soon.
<?php
}
?>
我省略了大部分的它的实际验证代码部分，所以我知道你看到的不完整。我不明白的是，如果没有这个AJAX部分，表单验证的工作方式就很好 - 客户端和服务器端，但是当我添加AJAX时，某些东西没有连接。感谢您的帮助提前。
编辑 有没有人有我的代码出错的建议？
编辑 好了，所以如果我把js/validation.php在action=""标签的形式和禁用码的AJAX部分，然后验证工作得很好，但我转发到一个网页，只是空白确认码。这在这个问题上有什么亮点吗？真的，任何帮助表示赞赏。我尝试过使用评论中给出的提示，但由于某种原因没有任何反应。它看起来像我的网页刷新，但没有确认信息，或任何东西。我完全失去了。
这并不回答你的验证问题，但我想指出，你可以使用$ .post（“test.php”，$（“＃testform”）序列化整个表单。 （））; ..不需要获取每个值并将它们作为一个字符串粘在一起。您使用的是Apache错误日志和Firefox错误控制台，您是否使用 – Stephen
？找出ajax错误是非常宝贵的。 –
@Stephen - 所以在这种情况下，我可以将其重写为：'$ .post（“validation.php”，$（'＃contact_form'）。serialize（））;'摆脱'var dataString = blahblahblah; '部分？ – Michael