我正在使用Firebase。我想检查我的应用程序的重复数据。目前我让用户输入姓名和电子邮件。但是,如果用户第二次输入相同的名称和电子邮件,它也会被添加到数据库中。 如何解决这个 这里是我的代码:如何检查Firebase中的重复数据
package com.example.zaid_pc.mpd2;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
import com.google.firebase.database.DataSnapshot;
import com.google.firebase.database.DatabaseError;
import com.google.firebase.database.DatabaseReference;
import com.google.firebase.database.FirebaseDatabase;
import com.google.firebase.database.ValueEventListener;
public class tournament extends AppCompatActivity {
private EditText etTournament;
private EditText emailTournament;
private DatabaseReference mDatabaseRefernce;
Button btnTournament;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_tournament);
etTournament = (EditText)findViewById(R.id.etTournament);
emailTournament = (EditText)findViewById(R.id.emailTournament);
btnTournament = (Button)findViewById(R.id.btnTournament);
mDatabaseRefernce = FirebaseDatabase.getInstance().getReference().child("People Registered");
btnTournament.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
final String name = etTournament.getText().toString().trim();
final String email = emailTournament.getText().toString().trim();
//mDatabaseRefernce.child("Name").setValue(name);
//mDatabaseRefernce.child("Email").setValue(email);
final DatabaseReference peopleRegisered = mDatabaseRefernce.push();
peopleRegisered.child("Name").setValue(name);
peopleRegisered.child("Email").setValue(email);
Toast.makeText(tournament.this, "You will be notified via email", Toast.LENGTH_LONG).show();
finish();
}
});
}
}
的[火力地堡的android:使用户名唯一]可能的复制(http://stackoverflow.com/questions/35243492/firebase-android-make-username-unique) – faruk
发布火力地堡数据库结构 – Lingeshwaran