将值传递给Django模型属性

Question

我正在构建一个文件上传页面，其中文件将以其名称中的不同前缀保存（get_file_path函数使用instance.mname），但会通过相同的上载模型/表单。我想要在mname ='prefix'中的窗体视图中声明前缀。我怎样才能从视图中传递这个值来形成？

谢谢！

models.py

class Upload(models.Model): 

    mname = # need it to be passed 
    document = models.FileField(upload_to=get_file_path, validators=[validate_file_extension]) 
    upload_date=models.DateTimeField(auto_now_add =True) 

forms.py

class UploadForm(forms.ModelForm): 
    class Meta: 
     model = Upload 
     fields = ('document',) 

views.py

def uploadFile(request): 
    if request.method == "POST": 

     file = UploadForm(request.POST, request.FILES, mname='....') 
     if file.is_valid(): 
      file.save() 

Answer 1

您可以将参数添加到窗体的__init__：

UploadForm(forms.Form): 

    def __init__(self, path, *args, **kwargs): 
     super(UploadForm, self).__init__(*args, **kwargs) 
     self.fields['document'] = forms.FileField(upload_to=path, validators=[validate_file_extension]) 

而与此参数初始化形式：

file = UploadForm(request.POST, request.FILES, path='...')