实际上,正如评论中提到的,当使用TypeScript v2.3.x进行编译时,您的代码片段可以正常工作。
您可能首先需要通过tsc --v
来检查TypeScript版本,并根据需要进行更新。
我已经采取了你提到的snippet from GitLab,并测试它是否按预期工作。下面的两个基本的例子安排并同时返回“真”与“假”:
/**
* Example that arranges the function to return 'true'
*/
public exampleTrue(): boolean {
let registerdata = { userid: 1001 };
let tested_users = [];
return this.register.user_checking(registerdata, tested_users);
}
/**
* Example that arranges the function to return 'false'
*/
public exampleFalse(): boolean {
let registerdata = { userid: 1001 };
let tested_users = [];
this.tested_users[registerdata.userid] = 'foo';
return this.register.user_checking(registerdata, this.tested_users);
}
为了记录在案,这里是你的类不做任何修改:
import {autoinject} from 'aurelia-framework';
import {HttpClient, json} from 'aurelia-fetch-client';
@autoinject
export class Register {
heading:string = 'sTeam register';
registerdata = {};
passwordmatch = true;
tested_users = {}; //in coffee this is 'tested_users = {}'
/**
* CoffeeScript(AngularJS based) code as follows.
* ------------------------------
* S.tested_users =() ->
* tested_users
* ------------------------------
* @param tested_users
* @returns {any}
*/
tested_users_check(tested_users) {
return tested_users;
}
/**
* CoffeeScript(AngularJS based) code as follows.
* ------------------------------
* S.user_checking = ->
* S.registerdata.userid and typeof tested_users[S.registerdata.userid] == 'undefined'
* ------------------------------
* @param registerdata
* @param tested_users
* @returns {number}
*/
user_checking(registerdata, tested_users) {
return registerdata.userid && typeof tested_users[registerdata.userid] == 'undefined';
}
/**
* CoffeeScript(AngularJS based) code as follows.
* ------------------------------
* S.user_available = ->
* typeof tested_users[S.registerdata.userid] != 'undefined' and !tested_users[S.registerdata.userid]
* ------------------------------
* @param registerdata
* @param tested_users
*/
user_available(registerdata, tested_users) {
typeof tested_users[registerdata.userid] != 'undefined' && !tested_users[registerdata.userid];
}
/**
* CoffeeScript(AngularJS based) code as follows.
* ------------------------------
* S.user_taken = ->
* typeof tested_users[S.registerdata.userid] != 'undefined' and tested_users[S.registerdata.userid]
* ------------------------------
* @param registerdata
* @param tested_users
*/
user_taken(registerdata, tested_users) {
typeof tested_users[registerdata.userid] != 'undefined' && tested_users[registerdata.userid];
}
/**
* CoffeeScript(AngularJS based) code as follows.
* ------------------------------
* S.register = ->
* S.registerdata.group = 'techgrind'
* steam.post('register', S.registerdata).then(handle_request)
* ------------------------------
* @param registerdata
*/
register(registerdata) {
registerdata.group = 'kaishr';
// Have to implement the steam post method call.
}
}
一点题外话我想要指出的是,利用TypeScript的强类型可能会非常有帮助。你的课程几乎不使用任何约束和类型声明。但也许,作为一个起点,你可能会得到一些小的调整,如:
// define a strong-typed array, constrained to numbers
// (assuming userid is a number)
tested_users: Array<number> = [];
// define the class 'RegisterData'
// forcing it to have a userid of type number
export class RegisterData {
public userid: number;
}
有了这个地方,你可以重构你的操作更有点走编译时的安全性和检查的充分利用,在你面前甚至运行你的应用程序像这样:
public user_checking(registerdata: RegisterData, tested_users: Array<number>): boolean {
return registerdata.userid && typeof tested_users[registerdata.userid] == 'undefined';
}
不要被咋一看,在仪式上看起来像很多开销。只有加入某些类型的,你已经做了以下内容:
- 强迫你的函数返回
boolean
- 强类型的RegisterData类
- 淘汰任何可能的类型不匹配的
userid
- 约束输入参数到强类型
最终,这将使您的编译器在您运行程序之前帮助您提供更好的信息。
希望这有助于...
您必须为方法 – Li357
@AndrewLi能否请你告诉我,我怎么能做到这一点声明返回类型('number')? –
'user_checking(registerdata,tested_users):number {...}' – Li357