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） 我正在研究一个代码...几乎完成，但我坚持最后一件事， 我需要找到一种方法来编辑客户端的信息，当用户希望。 这是我的代码...任何人都可以告诉我有什么问题吗？ ：编辑一个二叉树结构的节点
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
ifstream infile;
ofstream outfile;
struct INFO {
int id;
string name;
unsigned balance;
long phone;
};
class Node
{
public:
INFO data;
Node *left;
Node *right;
Node() {
data.id = 0;
data.name = "NULL";
data.phone = 0;
data.balance = 0;
}
Node(INFO a)
{
data = a;
left = 0;
right = 0;
}
};
class Tree
{
public:
Node *root;
INFO inf;
Node *zero;
Tree()
{
root = 0;
}
bool insert(INFO inf)
{
if (root == 0)
{
root = new Node(inf);
return true;
}
Node *p = root;
Node *q = root;
while (p != 0)
{
q = p;
if (p->data.id == inf.id)
return false;
if (p->data.id > inf.id)
p = p->left;
else
p = p->right;
}
if (inf.id < q->data.id)
q->left = new Node(inf);
else
q->right = new Node(inf);
return true;
}
bool searchid(Node *p, int y)
{
if (p != 0) {
if (p->data.id == y) {
cout << "ID: ";
cout << p->data.id << "\t";
cout << "Name: ";
cout << p->data.name << "\t";
cout << "Balance: ";
cout << p->data.balance << "\t";
cout << "Phone number: ";
cout << p->data.phone << endl;
cout << "_________________" << endl;
return true;
}
}
if (p->left != 0) {
if (searchid(p->left, y)) {
return true;
}
}
if (p->right != 0) {
if (searchid(p->right, y)) {
return true;
}
}
return false;
}
Node SAD(int id) {
Node *p = root;
if (p->data.id == id) {
Node *q = p;
return *p;
}
if (p->left != 0)
SAD(p->left->data.id);
if (p->right != 0)
SAD(p->right->data.id);
return *zero;
}
void edit(int q) {
Node p = SAD(q);
cout << "The ID is: " << p.data.id << endl;
cout << "The account owner: ";
cout << p.data.name << endl;
cout << "Do you want to edit the owner?(Y/N) ";
char x;
cin >> x;
if (x == 'Y' || x == 'y') {
string New;
cout << "Enter the new owner name: ";
cin >> New;
p.data.name = New;
}
cout << "The Balance in the account is: ";
cout << p.data.balance << endl;
cout << "Do you want to edit the balance?(Y/N) ";
cin >> x;
if (x == 'Y' || x == 'y') {
int New;
cout << "Enter the new Balance: ";
cin >> New;
p.data.balance = New;
}
cout << "The phone number is: ";
cout << p.data.phone << endl;
cout << "Do you want to edit the phone number?(Y/N) ";
cin >> x;
if (x == 'Y' || x == 'y') {
long New;
cout << "Enter the new phone number";
cin >> New;
p.data.phone = New;
}
cout << p.data.id << " " << p.data.name << " " << p.data.balance << " " << p.data.phone << endl;
insert(p.data);
}
void print(Node *p)
{
if (p != 0) {
cout << "ID: ";
cout << p->data.id << "\t";
cout << "Name: ";
cout << p->data.name << "\t";
cout << "Balance: ";
cout << p->data.balance << "\t";
cout << "Phone number: ";
cout << p->data.phone << endl;
cout << "_______________________________________________________________" << endl<<endl;
}
if (p->left != 0)
print(p->left);
if (p->right != 0)
print(p->right);
}
void store(Node *p)
{
if (p != 0) {
outfile << "ID: ";
outfile << p->data.id << " ";
outfile << "Name: ";
outfile << p->data.name << " ";
outfile << "Balance: ";
outfile << p->data.balance << " ";
outfile << "Phone number: ";
outfile << p->data.phone << endl;
outfile << "_______________________________________________________________" << endl;
}
if (p->left != 0)
store(p->left);
if (p->right != 0)
store(p->right);
}
bool searchname(Node *p, string x)
{
Node *q = root;
q = p;
while (p != 0) {
if (p->data.name == x) {
cout << "ID: " << p->data.id << "\t";
cout << "Name: " << p->data.name << "\t";
cout << "Balance: " << p->data.balance << "\t";
cout << "Phone number: " << p->data.phone << endl;
}
else {
}
}
}
};
void main()
{
outfile.open("clients.txt");
int opt;
Tree t;
int m = 1;
while (m != 0) {
cout << "Choose an option:" << endl << "1- To Add new clients." << endl << "2- To Display the clients." << endl << "3- To Store the clients in a Text Document." << endl << "4- To Search for a specific client through it's ID." << endl << "5- To Edit a specific client's information" << endl << "6- To Delete a specific client." <<endl<<"7- Exit."<< endl;
cin >> opt;
switch (opt) {
case 1:
int n;
cout << "Enter the amount of clients: ";
cin >> n;
INFO *arr;
arr = new INFO[n];
cout << "Enter the elements of the array: " << endl;
for (int i = 0; i < n; i++)
{
cout << "Client #" << i + 1 << endl << "-----------" << endl;
cout << "Enter the ID: ";
cin >> arr[i].id;
cout << "Enter the name of the client: ";
cin >> arr[i].name;
cout << "Enter the balance: ";
cin >> arr[i].balance;
cout << "Enter the phone number: ";
cin >> arr[i].phone;
t.insert(arr[i]);
}
break;
case 2:
t.print(t.root);
break;
case 3:
t.store(t.root);
cout << "Saved!" << endl << "in directory: C:/Users/Taiseer/Documents/Visual Studio 2015/Projects/ADS Project/ADS Project" << endl;
break;
case 4:
cout << endl;
int s;
cout << "What element do you want to search for? ";
cin >> s;
if (t.searchid(t.root, s) == false) {
cout << " Not here.... :(\n";
}
cout << endl;
break;
case 5:
char x;
cin >> x;
if (x == 'y' || x == 'Y') {
int id;
cout << "Enter the id you want to edit: ";
cin >> id;
t.edit(id);
}
else
return;
break;
case 6:
break;
case 7:
m = 0;
break;
default:
cout << "lol" << endl;
}
}
}
解决此类问题的正确工具是您的调试器。在*堆栈溢出问题之前，您应该逐行执行您的代码。如需更多帮助，请阅读[如何调试小程序（由Eric Lippert撰写）]（https://ericlippert.com/2014/03/05/how-to-debug-small-programs/）。至少，您应该\编辑您的问题，以包含一个[最小，完整和可验证]（http://stackoverflow.com/help/mcve）示例，该示例再现了您的问题，以及您在调试器。 –
你是对的...如果我知道Algorithem解决我的问题... –