2017-06-18 132 views
1

我试图使我的应用程序连接到使用Retrofit 2的本地Web服务,但我总是得到这个错误。我确定Web服务正在响应,因为我在Firefox中使用了一个使@GET请求和返回成功的工具,并返回了正确的JSON。改装2错误:java.net.SocketTimeoutException:未能连接到10000m后的/192.168.86.1(端口8080)

在android中它甚至没有连接。

这是我的MainActivity:

public class MainActivity extends AppCompatActivity { 

    private String API_BASE_URL="http://192.168.1.32:8080/economarket-restService/resources/androidTest/";   

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 

     OkHttpClient.Builder httpClient = new OkHttpClient.Builder();    

     Retrofit.Builder builder = new Retrofit.Builder() 
       .baseUrl(API_BASE_URL) 
       .addConverterFactory(GsonConverterFactory.create()); 

     Retrofit retrofit = builder.client(
       httpClient.build() 
     ).build(); 

     ContatoService contato = retrofit.create(ContatoService.class); 

     Call<Contato> repos = contato.listRespos(); //EconomarketService     

     repos.enqueue(new Callback<Contato>() { 
      @Override 
      public void onResponse(Call<Contato> call, Response<Contato> response) { 
       Contato contato = response.body(); 
       Toast.makeText(getBaseContext(), "Return" + contato.getName(), Toast.LENGTH_LONG).show(); 
       Log.d("Retorno",response.toString()); 
      } 

      @Override 
      public void onFailure(Call<Contato> call, Throwable t) { 
       Toast.makeText(getBaseContext(), "Return" + t.toString(), Toast.LENGTH_LONG).show(); 
       Log.d("Retorno",t.toString()); 
      } 
     });      
    }   
} 

我的接口:

public interface ContatoService { 
    @GET("retorna/") 
    Call<Contato> listRespos(); 
} 

模型类(Contato):

public class Contato { 

    @SerializedName("name") 
    private String name; 

    @SerializedName("phone") 
    private int phone; 

    @SerializedName("likes") 
    private int likes; 

    @SerializedName("location") 
    private Location location; 


    public String getName() { 
     return name; 
    } 

    public void setName(String name) { 
     this.name = name; 
    } 

    public int getPhone() { 
     return phone; 
    } 

    public void setPhone(int phone) { 
     this.phone = phone; 
    } 

    public int getLikes() { 
     return likes; 
    } 

    public void setLikes(int likes) { 
     this.likes = likes; 
    } 



    public Location getLocation() { 
     return location; 
    } 

    public void setLocation(Location location) { 
     this.location = location; 
    } 
} 

模型类(地点):

public class Location{ 

} 
+0

使用手机浏览器,而不是服务器本身的Firefox工具。如果你无法连接,这是一个防火墙问题 –

+0

好的,我做到了。我在手机浏览器上测试过,它也正确地返回了json。 – Apolo

+0

在您的帖子标题中,“无法连接到/ 192.168.86.1”。这与您的代码中显示的URL不一样 –

回答

1

问题解决了!问题是API_BASE_URL,THI URL应该只有:

"http://192.168.1.32:8080/"

和URL的其余部分应在接口上:

@GET("economarket-restService/resources/androidTest/retorna/‌​"). 

这一切都归结到申报的根URL_BASE中的URL和url目录访问必须位于接口上。

+0

'@ GET'只是附加到基本网址,所以我很惊讶这是修复 –

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