2014-12-05 52 views
0

晚上好,我的问题是与以下几点:C#为模板的结构:无法隐式转换

public struct vector2D<T1> 
{ 
    public T1 m_w; 
    public T1 m_h; 

    // Irrelevant stuff removed (constructor, other overloader's) 

    public static bool operator !=(vector2D<T1> src, T1 dest) 
    { 
     return (((dynamic)src.m_w != (dynamic)dest) || ((dynamic)src.m_h != (dynamic)dest)); 
    } 

    public static bool operator ==(vector2D<T1> src, T1 dest) 
    { 
     return (((dynamic)src.m_w != (dynamic)dest) || ((dynamic)src.m_h != (dynamic)dest)); 
    } 

    public static bool operator !=(vector2D<T1> src, vector2D<T1> dest) 
    { 
     return (((dynamic)src.m_w != (dynamic)dest.m_w) || ((dynamic)src.m_h != (dynamic)dest.m_h)); 
    } 

    public static bool operator ==(vector2D<T1> src, vector2D<T1> dest) 
    { 
     return Equals(src, dest); 
    } 
} 

现在,我得到了错误的是:

Error 1 Operator '!=' cannot be applied to operands of type 'vector2D<int>' and 'vector2D<uint>' 
Error 2 Cannot implicitly convert type 'vector2D<uint>' to 'vector2D<int>' 

现在我知道的编译器不知道如何“铸”与下面的代码片段:

vector2D<uint>[] Something = new vector2D<uint>[2]; // Pretend it has values... 
Dictonary<uint, vector2D<int>> AnotherThing = new Dictonary<uint, vector2D<int>>(); // Pretend it has values... 

if (AnotherThing[0] != Something[0]) { ... } 

AnotherThing[0] = Something[0]; 

我试过几件事,只是他们要么给我更多错误,不工作或不工作。所以我的问题是我将如何去做“铸造”?

也可能不错,我通常使用C++编程,所以C#让我感到惊讶了好几次。如果上面的代码给你做恶梦,还提前抱歉。

回答

2

你需要告诉编译器如何将类型转换 '的Vector2D < UINT>' 到 '的Vector2D < int>的'

public static implicit operator vector2D<T1>(vector2D<uint> src) 
     { 
      return new vector2D<T1> 
       { 
        m_h = (T1)Convert.ChangeType(src.m_h, typeof(T1)), 
        m_w = (T1)Convert.ChangeType(src.m_w, typeof(T1)), 
       }; 
     } 
+0

谢谢你,就像一个魅力。我尝试了类似的东西,但没有奏效,我明白为什么它没有,反正再次感谢你。 – SharkBytes 2014-12-05 03:26:57