2016-11-22 145 views
0

我目前正试图实现JsonObjectRequest。我正在寻找一个位置并试图获取该地点的信息。但是,jsObjRequest(JsonObjectRequest类型)存在问题 - 即使它在检查监视列表时不为null,也会抛出空指针异常。我很困惑,为什么。下面的代码:JsonObjectRequest保持抛出空指针异常,当它不为空

private static final HttpTransport HTTP_TRANSPORT = new NetHttpTransport(); 
private static final String API_KEY = "AIzaSyBlOhVQWuyQGwlAGZnDo81Aeg50UJbFrfw"; 

private static final String PLACES_SEARCH_URL = 
     "https://maps.googleapis.com/maps/api/place/search/json?"; 
private static final String PLACES_TEXT_SEARCH_URL = 
     "https://maps.googleapis.com/maps/api/place/search/json?"; 
private static final String PLACES_DETAILS_URL = 
     "https://maps.googleapis.com/maps/api/place/details/json?"; 

private double _latitude; 
private double _longitude; 
private double _radius; 

/** 
* Searching places 
* @param latitude - latitude of place 
* @params longitude - longitude of place 
* @param radius - radius of searchable area 
* //@param types - type of place to search 
* @return list of places 
* */ 
public PlacesList search(double latitude, double longitude, double radius/*, String types*/) 
     throws Exception { 

    String url = PLACES_SEARCH_URL + "key=" + API_KEY + "&location=" + latitude + "," + longitude + "&radius=" + radius; 
    System.out.println(url); 
    JsonObjectRequest jsObjRequest = new JsonObjectRequest 
      (Request.Method.GET, url, null, new Response.Listener<JSONObject>() { 
       @Override 
       public void onResponse(JSONObject response) { 
        try { 
         Log.d("SEARCH", "Part 1"); 
         VolleyLog.v("Response:%n %s", response.toString(4)); 
        } catch (JSONException e) { 
         Log.d("SEARCH", "Part 2 - Exception called"); 
         e.printStackTrace(); 
        } 
        catch (Exception e) 
        { 
         System.out.println("Exception caught in JsonObjectRequest"); 
        } 
       } 
      }, new Response.ErrorListener() { 
       @Override 
       public void onErrorResponse(VolleyError error) { 
        Log.d("SEARCH", "Part 3"); 
        VolleyLog.e("Error: ", error.getMessage()); 
       } 
      }); 
    ApplicationController.getInstance().addToRequestQueue(jsObjRequest); 
    return new PlacesList(); 
} 

它轻视包含行:ApplicationController.getInstance()addToRequestQueue(jsObjRequest);

下面的代码块是我们捕捉到了异常:

// Define a listener that responds to location updates 
LocationListener locationListener = new LocationListener() { 
    public void onLocationChanged(Location location) { 
     // Called when a new location is found by the network location provider. 
     Double lat = location.getLatitude(); 
     Double lon = location.getLongitude(); 
     PlacesList myPlaces = new PlacesList(); 
     try { 
      myPlaces = finder.search(lat, lon, 10); 
     } catch (Exception e) { 
      System.out.println("Could not find place. Exception in search."); 
     } 
     if (myPlaces.getMostLikelyPlace() != null) { 
      if (myPlaces.getMostLikelyPlace().getId() != null) { 
       Log.d("PLACEID", myPlaces.getMostLikelyPlace().getId()); 
       System.out.println(myPlaces.getMostLikelyPlace().getId()); 
      } 
     } 
    } 

,我们捕获的错误是这样的:

I/System.out的:https://maps.googleapis.com/maps/api/place/search/json?key=AIzaSyBlOhVQWuyQGwlAGZnDo81Aeg50UJbFrfw&location=43.816,-111.78199833333335&radius=10.0

I/System.out:找不到地方。搜索异常。

这里是什么文件说,大约JsonObjectRequest:https://developer.android.com/training/volley/request.html#request-json

我觉得我下面的文档上的说明完全一样。是否有任何理由为什么它会抛出该代码行?

回答

0

尝试这种设置对于凌空..

http://www.androidhive.info/2014/05/android-working-with-volley-library-1/

也许出了点问题抽射设置的项目。与我所有的时间发生..

+0

如果抽射设置做正确的并正在为其他东西工作..让我知道.. – Azi

+0

安装程序的作品,我没有得到相同的错误,但我在onErrorResponse VolleyError。当我尝试使用VolleyLog.e(“Error:”,error.getMessage())打印错误消息时,它告诉我什么都没有。它所说的是“E/Volley:[1] 2.onErrorResponse:Error:”。任何有关为什么这可能会发生的见解?非常感谢您的参与。 –