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我有一个带自动前进功能的jQuery滑块。但是我想知道如何在最后一张幻灯片到达后返回到第一张幻灯片。 currentSlide变量(保存我们正在查看的当前幻灯片的索引)只是越来越大,在到达最后一张幻灯片后不会返回零。我没有将滑块本身的所有jQuery脚本都包含进去,因为这会很大,而且我觉得没有必要。下面是代码:在到达最后一张幻灯片后返回第一张幻灯片 - 使用jQuery Slider
<html>
<head>
</head>
<body>
<div class="slider" data-slide="0">
<div class="slide"></div>
<div class="slide"></div>
<div class="slide"></div>
<div class="slide"></div>
</div>
<script type="text/javascript" src="js/jquery-1.7.2.js"></script>
<script type="text/javascript">
$(window).load(function(){
var currentSlide = $(".slider").attr("data-slide"); /*Every time a slide is viewed, the index number of that slide is added to an html5 data- attribute. That way, we know what slide we are on. This var stores that information. */
var timeOut = null;
(function autoAdvance(){
$('.sliderNav').find('.sliderTrigger' + (currentSlide)).trigger('click',[true]); /* Automatically click the trigger that will advance the slider to the next slide. */
currentSlide++;
timeOut = setTimeout(autoAdvance,5000);
})();
});
</script>
</body>
</html>
非常感谢,我简直不敢相信我没想到!只有一个问题:你需要改变currentSlide = 1;到currentSlide = 0;因为索引是基于零的。 –