$ _POST ['var']到MySQL DB中？

Question

我使用WAMP尝试和学习一点PHP和SQL。我试图从这里一个非常基本的表用户输入：

<form action="input.php" method="post" class="registration_form"/> 
    <fieldset> 
    <div class="elements"> 
     <label for="name">Username :</label> 
     <input type="text" id="name" name="name" size="25" /> 
    </div> 
    <div class="elements"> 
     <label for="e-mail">E-mail :</label> 
     <input type="text" id="e-mail" name="e-mail" size="25" /> 
    </div> 
    <div class="elements"> 
     <label for="Password">Password:</label> 
     <input type="password" id="Password" name="Password" size="25" /> 
    </div> 
    <div class="submit"> 
    <input type="hidden" name="formsubmitted" value="TRUE" /> 
     <input type="submit" value="Register" /> 
    </div> 
    </fieldset> 
</form> 

，我希望能够把输入和岗位的数据库。我一直在努力做到这一点，此代码：

<?php 
$servername = "localhost"; 
$username = "root"; 
$password = ""; 
$dbname = "test"; 

//Create connection 
$conn = new mysqli($servername, $username, $password, $dbname); 
//Check connection 
if ($conn->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 


$sql = "INSERT INTO MyGuests (name, email, password) 
VALUES ($_POST[name], $_POST[e-mail], $_POST[password])"; 

if ($conn->query($sql) === TRUE) { 
    echo "New record created successfully"; 
} else { 
    echo "Error: " . $sql . "<br>" . $conn->error;// 
} 

$conn->close(); 
var_dump('name', 'e-mail', 'password'); 

?> 

当我尝试并插入“”在$ _POST [“名称”]在我得到一个错误：

Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) in C:\wamp\www\input.php on line 16 

当我尝试删除“”我得到这个错误：

Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) in C:\wamp\www\input.php on line 16 

我也试着设置变量的代码的顶部：

<?php 
$servername = "localhost"; 
$username = "root"; 
$password = ""; 
$dbname = "test"; 
$name=$_POST['name'] 

//Create connection 
$conn = new mysqli($servername, $username, $password, $dbname); 
//Check connection 
if ($conn->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 


$sql = "INSERT INTO MyGuests (name, email, password) 
VALUES ('name','email', 'password'); 

if ($conn->query($sql) === TRUE) { 
    echo "New record created successfully"; 
} else { 
    echo "Error: " . $sql . "<br>" . $conn->error;// 
} 

$conn->close(); 
var_dump('name', 'e-mail', 'password'); 

?> 

这样，我结束了一个错误消息说：

(!) Parse error: syntax error, unexpected '$conn' (T_VARIABLE) in C:\wamp\www\input.php on line 9 

我可以用$ _ POST在另一个脚本呼应的名字，我不知道为什么它不会与SQL命令工作。如果有人愿意帮忙，并且/或者给我一些资源来学习/学习，我将不胜感激！

Answer 1

你有一个缺少 ';'后： $名称= $ _ POST [“名”]

Answer 2

嗨请注意一些要点

1）您将获得未定义指数的警告，因为你不检查有关张贴或没有价值。在使用值之前，我们应该使用isset()。

2）第二次尝试使用lowercase每当你给任何标签在php中确保没有错误存在，因为输入lowercase或uppercase。

3）尝试使用underscore，如果你的字长，所以使用e_mail;

所以，你可以使用这个php代码

 <?php 

     if(isset($_POST['register'])){ 
    $servername = "localhost"; 
    $username = "root"; 
    $password = ""; 
    $dbname = "test"; 
    $conn = new mysqli($servername, $username, $password, $dbname); 
    //Check connection 
    if ($conn->connect_error) { 
     die("Connection failed: " . $conn->connect_error); 
    } 

    $name = $_POST['name']; 
    $email = $_POST['e_mail']; 
    $password = $_POST['password']; 
    $sql = "INSERT INTO MyGuests(name, email, password) VALUES('$name','$email','$password')"; 

if ($conn->query($sql) === TRUE) { 
    echo "New record created successfully"; 
} else { 
    echo "Error: " . $sql . "<br>" . $conn->error;// 
} 

$conn->close(); 
     } 
     ?> 

我已经添加名称到您的submit按钮也发生了变化e-mail到e_mail和name="Password"到name="password"

<form action="input.php" method="post" class="registration_form"/> 
    <fieldset> 
    <div class="elements"> 
     <label for="name">Username :</label> 
     <input type="text" id="name" name="name" size="25" /> 
    </div> 
    <div class="elements"> 
     <label for="e-mail">E-mail :</label> 
     <input type="text" id="e_mail" name="e_mail" size="25" /> 
    </div> 
    <div class="elements"> 
     <label for="Password">Password:</label> 
     <input type="password" id="Password" name="password" size="25" /> 
    </div> 
    <div class="submit"> 
    <input type="hidden" name="formsubmitted" value="TRUE" /> 
     <input type="submit" value="Register" name="register" /> 
    </div> 
    </fieldset> 
</form>