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我是RxJava的新手。我有一个场景,我想调用第一个登录web服务(getLoginObservable
),如果成功,想调用另一个webservice(getFetchDataObservable
)来获取用户信息。RxAndroid接连拨打一个网络电话
如果登录成功,我有以下代码工作。但我无法弄清楚如何编码failure
的情况。
private void doLogin() {
emailAddress = editTextUsername.getText().toString();
final String password = editTextPassword.getText().toString();
showProgress(null, getString(R.string.loggingInPleaseWait));
getLoginObservable(editTextUsername.getText().toString(), password)
.map(response -> {
if (response.result) {
getPresenter().saveUserDetails(getContext(), emailAddress, true, response.dataObject.questionId, response.dataObject.question);
}
return response;
})
.flatMap(response -> {
return getFetchDataObservable();
})
.subscribe(res -> {
dismissProgress();
if (res.result) {
saveInformation(password, res);
} else {
ConstantsMethods.showOkButtonDialog(getContext(), res.message, null);
}
}, e -> {
dismissProgress();
if (e instanceof NoInternetConnectionException) {
ConstantsMethods.showOkButtonDialog(getContext(), getString(R.string.noInternetConnection), null);
}
Log.e(LoginFragment.class.getSimpleName(), e.getMessage());
});
}
private Observable<WsResponse<SecurityQuestion>> getLoginObservable(String userName, String password) {
return Observable.<WsResponse<SecurityQuestion>>create(subscriber -> {
getPresenter().doLogin(getActivity(), userName, password, appType,
new Callback<Void, WsResponse<SecurityQuestion>>() {
@Override
public Void callback(final WsResponse<SecurityQuestion> param) {
subscriber.onNext(param);
return null;
}
});
});
}
private Observable<WsResponse<PatientDataProfile>> getFetchDataObservable() {
return Observable.create(subscriber -> {
new AfPatientsPresenter().fetchPatientData(getContext(), emailAddress, "", new Callback<Void, WsResponse<PatientDataProfile>>() {
@Override
public Void callback(WsResponse<PatientDataProfile> param1) {
subscriber.onNext(param1);
subscriber.onComplete();
return null;
}
});
});
}
一样多,我知道RxJava,我能弄清楚,getLoginObservable(editTextUsername.getText().toString(), password)
观察到发送响应映射(map(response -> { ... }
),并且此映射返回响应flatmap(flatMap(response -> { ... }
)和它的响应发送给用户。在这里,我只是迷失了,我如何跳过(第二个网络电话)平面图flatMap(response -> { ... }
直接发送回应的订户在登录失败的情况下。而不是