if-statement取决于输入

Question

我想创建一个“简单”的方式来问一个人他们想要找到什么形状的区域。然后根据他们的输入找出形状的区域。我正在使用Python 2.7.3。以下是我迄今为止：

from math import pi 
c = "" 
r = "" 
x = (input("Do you have a [r]ectangle or a [c]ircle? ")) # Answer with r or c 
if x == "r": 
    l = (int(input("What is the length of your rectangle? "))) 
    w = (int(input("What is the width of your rectangle? "))) 
    print(l * w) 
elif x == "c": 
    r = (int(input("What is the radius of your circle? "))) 
    print(r ** 2 * pi) 
else: 
    print("Please enter request in lower case. ") 

Answer 1

from math import pi 
# use raw input (raw_input()) for the inputs... input() is essentially eval(input()) 
# this is how i would ask for input for a simple problem like this 
x = (raw_input("Do you have a [r]ectangle or a [c]ircle? ")) # Answer with r or c 
# use .lower() to allow upper or lowercase 
if x.lower() == "r": 
    l = (int(raw_input("What is the length of your rectangle? "))) 
    w = (int(raw_input("What is the width of your rectangle? "))) 
    print(l * w) 
elif x.lower() == "c": 
    r = (int(raw_input("What is the radius of your circle? "))) 
    print(r ** 2 * pi) 
else: 
    print("You didn't enter r or c.")