选择查询以获得SQL Server中的总记录数

Question

嗨，我有一个表与状态列。如何使用SQL获取记录总数，带有传递状态的记录总数和带有失败状态的记录总数？

Answer 1

我会写类似

select 
Count(*) as TotalRecords, 
Sum(case where status = 'Pass' then 1 else 0 end) as PassRecords, 
Sum(case where status = 'Fail' then 1 else 0 end) as FaileRecords 
from Table 

Answer 2

怎么是这样的：

SELECT Status, COUNT(*) 
FROM dbo.YourTable 
GROUP BY Status WITH ROLLUP 

这会工作，如果这两个状态（及格，不及格）是唯一的状态（否则你需要一个WHERE Status IN ('fail', 'pass')条件还） - 和WITH ROLLUP也将给你行的总数（以输出与Status = NULL）所有状态

Answer 3

您可以用case语句和聚合做到这一点：

select count(*), sum(case when status = 'pass' then 1 else 0 end) as pass, 
     sum(case when status = 'fail' then 1 else 0 end) as fail 
from t 

Answer 4

一对夫妇的其他替代品（SQL服务器2008+）查询：

DECLARE @foo TABLE([status] CHAR(4)); 

INSERT @foo SELECT 'pass' 
UNION ALL SELECT 'pass' 
UNION ALL SELECT 'fail'; 

-- option #1: 

SELECT [status], c = COUNT(*) 
FROM @foo 
GROUP BY GROUPING SETS(([status]),()); 

-- option #2: 

SELECT [status], c = COUNT(*) 
FROM @foo 
GROUP BY [status] 
UNION ALL 
SELECT NULL, COUNT(*) OVER() FROM @foo;