2015-02-06 199 views
0

我很清楚地知道@SecondaryTable注释是单个实体的字段映射到多张表,就好像这些表合并为一单身。
我在实现这个概念时遇到问题。 有3类需要被持续下去,@SecondaryTables:映射一个实体到多张表

的Class1其2个字段出4要被存储在2个其他不同的表

@Entity 
@Table(name = "MAIN_CAT") 
@SecondaryTables({ 

    @SecondaryTable(name = "CAT_1", pkJoinColumns = { 
      @PrimaryKeyJoinColumn(name = "CAT1_PK", referencedColumnName = "id") 
     }), 
    @SecondaryTable(name = "CAT_2", uniqueConstraints = { 
      @UniqueConstraint(columnNames = {"storyPart2"}) 
    }) 
}) 
public class Cat { 

    @[email protected] 
    private Long id; 

    private String catName; 

    @Column(table = "CAT_1") 
    private String storyPart1; // this field is going to be stored in CAT_1 

    @Column(table = "CAT_2") 
    private String storyPart2; // and so on 
    // getters and setters 
} 

2类:此类当持续存储时,将storyPart1字段存储在上述持久类中

@Entity 
@Table(name = "CAT_1") 
public class CatOne { 

    @Id 
    @GeneratedValue 
    @Column(name = "CAT1_PK") 
    private Long CAT1_PK; 

    @Column(name = "CATNAME_1") 
    private String catName1; 

    @Column(name = "CATAGE_1") 
    private String catAge1; 
    // getters and setters 
} 

3类:当持续将存储持久类storyPart2字段1

@Entity 
@Table(name = "CAT_2") 
public class CatTwo { 

    @Id 
    @GeneratedValue 
    private Long id; 

    @Column(name = "CATNAME_2") 
    private String catName2; 

    @Column(name = "CATAGE_2") 
    private String catAge2; 
    // getters and setters 
} 

在数据库中创建的3个表是这个类:

对于第1类:

CREATE TABLE main_cat 
(
    id bigint NOT NULL, 
    catname character varying(255), 
    CONSTRAINT main_cat_pkey PRIMARY KEY (id) 
) 

对于2类:

CREATE TABLE cat_1 
(
    storypart1 character varying(255), 
    cat1_pk bigint NOT NULL, 
    catage_1 character varying(255), 
    catname_1 character varying(255), 
    CONSTRAINT cat_1_pkey PRIMARY KEY (cat1_pk), 
    CONSTRAINT fk_kvtvo6nrv78wxkm0kv01k9kdq FOREIGN KEY (cat1_pk) 
     REFERENCES main_cat (id) MATCH SIMPLE 
     ON UPDATE NO ACTION ON DELETE NO ACTION 
) 

对于第3类:

CREATE TABLE cat_2 
(
    storypart2 character varying(255), 
    id bigint NOT NULL, 
    catage_2 character varying(255), 
    catname_2 character varying(255), 
    CONSTRAINT cat_2_pkey PRIMARY KEY (id), 
    CONSTRAINT fk_2duj6ebg3504x18mlw2xkpvg6 FOREIGN KEY (id) 
     REFERENCES main_cat (id) MATCH SIMPLE 
     ON UPDATE NO ACTION ON DELETE NO ACTION, 
    CONSTRAINT uk_5ko8732qslvvx98gy0q666qrf UNIQUE (storypart2) 
) 

的问题是,而不是插入在CAT_1一个记录,它触发2个插入用于相同。在CAT_2中插入记录会发生同样的情况。

  Cat cat = new Cat(); 

     cat.setCatName("CAT Name"); 
     cat.setStoryPart1("STORYPART1"); 
     cat.setStoryPart2("STORYPART2"); 

     CatOne catOne = new CatOne(); 

     catOne.setCatAge1("10"); 
     catOne.setCatName1("catName1"); 

     CatTwo catTwo = new CatTwo(); 

     catTwo.setCatAge2("12"); 
     catTwo.setCatName2("catName2"); 

     session.save(cat); 
     session.save(catOne); 
     session.save(catTwo); 

声明:

Hibernate: insert into CAT_1 (storyPart1, CAT1_PK) values (?, ?) 
Hibernate: insert into CAT_1 (CATAGE_1, CATNAME_1, CAT1_PK) values (?, ?, ?) 

由于单个插入语句的分裂成2语句时,Hibernate抛出此错误。

Caused by: org.postgresql.util.PSQLException: ERROR: insert or update 
on table "cat_1" violates foreign key constraint 
"fk_kvtvo6nrv78wxkm0kv01k9kdq" Detail: Key (cat1_pk)=(2) is not 
present in table "main_cat". 

看起来像我已经以错误的方式实现了@SecondaryTable概念。如何让Hibernate在这种情况下触发单个插入呢?

回答

2

如果您已经使用某个表作为实体的辅助表,那么将该表映射到另一个实体也不是一个好主意。次表应该被理解为指定实体的另一个表格,只有通过该实体才能管理。

如果您已经有二手表的实体,那么使用普通实体映射@OneToOne@ManyToOne

+0

没有必要对这些,session.save(Catone的); session.save(catTwo); – 2015-02-06 14:26:34

相关问题