与加密混淆

Question

我正试图编写一个程序，以随机顺序从1到26的数字生成一个列表，然后使用该列表'加密'给定的单词，以便字母的第n个字母是映射到随机列表中的第n个数字。例如：

随机列表是：

[8,2,25,17,6,9,12,19,21,20,18,3,15,1,11,0,23,14,4,7,24,5,10,13,16,22] 

这意味着字act变得[8,25,7]和字xyzzy变得[13,16,22,22,16]。

我有下面的代码，但我不知道如何着手：

#8a 
def randomalpha(): 
    a=[0]*26 
    count = 0 
    while count < 25: 
     r = randrange(0,26) 
     if r not in a: 
      a[count] = r 
      count += 1 
    return(a) 
print(f()) 
#8b 
ls=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'] 
def encrypt(alphabet): 
    a=randomalpha() 
    count=0 
    b=input('enter a word') 
    for i in b:    #not sure if i am ok up to here but this is when i got really confused 


print(encrypt(ls)) 

Answer 1

import random 
import string 

def randomalpha(): 
    nums, result = range(26), [] # [0, 1, 2, 3, ... --> 25] 
    random.shuffle(nums) 
    for i in range(26): 
     result.append(nums.pop()) 
    return result 

def encrypt(s): 
    alphabet = list(string.lowercase) # ['a', 'b', 'c', ... --> 'z'] 
    key = dict(zip(alphabet, randomalpha())) 
    return ''.join([str(key[ltr]) for ltr in s]) 

参考文献：

• Dictionaries ({'a': 1, 'b': 2, ... --> 'z': 26})
• List Comprehensions (\[elem for elem in iterable\])
• string.join(iterable)
• zip(*iterables) (zip(\['a', 'b', 'c'\], \[1, 2, 3\]) =>\[('a', 1), ('b', 2), ('c', 3)])

Answer 2

我对此采取：

from string import ascii_lowercase 
from random import shuffle 

def char2num(chars): 
    r = range(len(chars)) 
    shuffle(r) 
    return dict(zip(chars, r)) 

def encrypt(s, lookup): 
    return ' '.join(str(lookup[ch]) for ch in s) 

print encrypt('cat', char2num(ascii_lowercase)) 

从我有工作，并返回随机非重复整数列表...第一个代码