shell脚本-s和-Sd代码工作不正常

Question

我有以下代码：

#Option -s for each set of files with the same name, presents sorted by size# 

elif [ $1 = "-S" ] 
then 
    shift 
    for i in $* 
    do 
     find $i -type f -print|while read F1 
      do 

       basename "${F1}" 
      done | sort | uniq -d | while read F2 
      do 
        find $i -type f -name "${F2}" -exec ls -l -S -R '{}' \; 
      done   
     done 

#Option -d performs sorting in descending order. 

elif [ $1 = "-d" ] 
then 
    shift 
    for i in $* 
    do 
     find $i -type f -print|while read F1 
      do 

       basename "${F1}" 
      done | sort | uniq -d | while read F2 
      do 
        find $i -type f -name "${F2}" -exec ls -l '{}' \; 
      done   
     done 

我应该按大小用命令-S，然后与-Sd递减顺序打印出来。我的输出似乎没有这样做。在这一点上，我无法弄清楚我的代码有什么问题。

-rw-r--r-- 1 quetzal quetzal 33 Out 7 20:27 aa/cc/t1 
-rw-r--r-- 1 quetzal quetzal 8 Out 7 20:36 aa/t1 
-rw-r--r-- 1 quetzal quetzal 0 Out 8 08:16 aa/cc/t2 
-rw-r--r-- 1 quetzal quetzal 0 Out 8 08:15 aa/t2 
-rw-r--r-- 1 quetzal quetzal 16 Out 8 08:16 aa/cc/t4 
-rw-r--r-- 1 quetzal quetzal 0 Out 10 12:53 aa/dd/t4 

Answer 1

反转排序是这样的：

elif [ $1 = "-d" ] 
then 
shift 
for i in $* 
do 
    find $i -type f -print|while read F1 
     do 

      basename "${F1}" 
     done | sort -r | uniq -d | while read F2 
     do 
       find $i -type f -name "${F2}" -exec ls -l '{}' \; 
     done   
    done