2016-09-20 117 views
-1

您好我从Switch between two frames in tkinter回答一些代码,即时尝试修改,以便在StartPage类中的按钮可以在PageOne类中调用一个称为msg的函数。Tkinter在另一个类中的调用函数

但是我得到这个错误:

AttributeError: 'Frame' object has no attribute 'msg'

这是到目前为止,我标出来我对代码进行了修改的代码。

import tkinter as tk # python3 
#import Tkinter as tk # python 

TITLE_FONT = ("Helvetica", 18, "bold") 

class SampleApp(tk.Tk): 

    def __init__(self, *args, **kwargs): 
     tk.Tk.__init__(self, *args, **kwargs) 

     # the container is where we'll stack a bunch of frames 
     # on top of each other, then the one we want visible 
     # will be raised above the others 
     container = tk.Frame(self) 
     container.pack(side="top", fill="both", expand=True) 
     container.grid_rowconfigure(0, weight=1) 
     container.grid_columnconfigure(0, weight=1) 

     self.frames = {} 
     for F in (StartPage, PageOne, PageTwo): 
      page_name = F.__name__ 
      frame = F(parent=container, controller=self) 
      self.frames[page_name] = frame 

      # put all of the pages in the same location; 
      # the one on the top of the stacking order 
      # will be the one that is visible. 
      frame.grid(row=0, column=0, sticky="nsew") 

     self.show_frame("StartPage") 

    def show_frame(self, page_name): 
     '''Show a frame for the given page name''' 
     frame = self.frames[page_name] 
     frame.tkraise() 


class StartPage(tk.Frame): 

    def __init__(self, parent, controller): 
     tk.Frame.__init__(self, parent) 
     self.controller = controller 

     self.parent = parent #<-- my mod 

     label = tk.Label(self, text="This is the start page", font=TITLE_FONT) 
     label.pack(side="top", fill="x", pady=10) 

     button1 = tk.Button(self, text="Go to Page One", 
          command=lambda: controller.show_frame("PageOne")) 
     button2 = tk.Button(self, text="Go to Page Two", 
          command=lambda: controller.show_frame("PageTwo")) 
     self.button3 = tk.Button(text='Calling msg in another class', command=self.parent.msg)#<-- my mod 
     button1.pack() 
     button2.pack() 
     button3.pack()#<-- my mod 

class PageOne(tk.Frame): 

    def __init__(self, parent, controller): 
     tk.Frame.__init__(self, parent) 
     self.controller = controller 

     self.parent = parent #<-- my mod 

     label = tk.Label(self, text="This is page 1", font=TITLE_FONT) 
     label.pack(side="top", fill="x", pady=10) 
     button = tk.Button(self, text="Go to the start page", 
          command=lambda: controller.show_frame("StartPage")) 
     button.pack() 

    def msg(self): #<-- my mod 
     print("IT WORKS!!") 

class PageTwo(tk.Frame): 

    def __init__(self, parent, controller): 
     tk.Frame.__init__(self, parent) 
     self.controller = controller 
     label = tk.Label(self, text="This is page 2", font=TITLE_FONT) 
     label.pack(side="top", fill="x", pady=10) 
     button = tk.Button(self, text="Go to the start page", 
          command=lambda: controller.show_frame("StartPage")) 
     button.pack() 


if __name__ == "__main__": 
    app = SampleApp() 
    app.mainloop() 

任何人都可以帮我吗?

+1

你做了'container = tk.Frame(self)',所以'container'是一个'Frame',然后在后续循环中将它作为'parent'传递。这意味着'self.parent'是对一个基本的'Frame'的引用,它没有你的额外'msg'方法,而不是你扩展的子类。 – TigerhawkT3

+0

我不明白。所以我该怎么做? –

回答

0

由于您正在实例化循环中的所有类,因此在它们之间添加引用的最简单方法可能是在该循环之后执行。从类内部除去这些引用,因为它们在实例化之后才会有效。请注意0​​不再创建或打包在StartPage中,而是在SampleApp中。

for F in (StartPage, PageOne, PageTwo): 
    ... 

self.frames['StartPage'].pageone = self.frames['PageOne'] 
self.frames['StartPage'].button3 = tk.Button(
           text='Calling msg in another class', 
           command=self.frames['StartPage'].pageone.msg) #<-- my mod 
self.frames['StartPage'].button3.pack() #<-- my mod 
+0

很好用。谢谢!但是在StartPage和PageOne类之间添加引用很难吗?很抱歉,因为我是python的新成员,所以感到非常好奇。无论如何感谢您的帮助! –

+0

@MichaelCraig - 如果你有一个类的对象创建另一个类的实例,而后者需要引用前者,那么你只需传递一个引用(例如'class A:def __init __(self):b = B(self) ')。在这里,虽然你创建了所有这些对象在同一级别,其中一个恰好需要引用另一个。由于您无法引用尚不存在的内容,因此解决方案是首先创建所有内容,然后添加引用。 – TigerhawkT3