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我从DB拉动疾病和复选框呈现他们在前端:Laravel复选框许多一对多的关系
<div class="col-lg-12 col-md-12 col-sm-12 col-xs-12">
@foreach($diseases as $disease)
<div class="col-md-6">
<div class="form-group">
<label>{{ Form::checkbox('diseases','0','',
['class' => 'grey','data-id'=> $disease->id]) }}
{{$disease->title}}
</label>
<div class="clearfix"></div>
</div>
</div>
@endforeach
</div>
一旦我提交表单,我得到的$request->diseases
这样的结果:
1:"1"
2:"1"
3:"0"
4:"1"
5:"0"
6:"0"
...
其中第一个数字代表disease_id
和其它一个呈现的复选框是否被选中或没有。关系到数据透视表的模型中正确,和我尝试在控制器做的是:
if ($request->has('diseases')) {
$patient->diseases()->sync($request->diseases);
}
但这种失败,错误:
Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key
constraint fails (`db_name`.`disease_patient`, CONSTRAINT `disease_patient_patient_id_foreign`
FOREIGN KEY (`patient_id`) REFERENCES `patients` (`id`) ON DELETE CASCADE) (SQL: insert into
`disease_patient` (`disease_id`, `patient_id`)
values (17, {"1":"0","2":"0","3":"1","4":"1","5":"1","6":"1","7":"1","8":"1","9":"0","10":"1","11":"0","12":"1","13":"0","14":"0","15":"0","16":"0","17":"0","18":"0","19":"0","20":"0","21":"0","22":"0","23":"0"}))
关系里面Patient
型号:
protected $guarded = ['id'];
public function diseases()
{
return $this->belongsToMany('App\Disease', 'disease_patient', 'disease_id', 'patient_id');
}
编辑:
当我做:
$diseases = array_keys(array_filter(json_decode($request->diseases, true)));
return $diseases;
我得到的ID列表,像这样:
0:1
1:2
2:8
3:14
4:15
5:21
和错误:
(SQL: insert into `disease_patient` (`disease_id`, `patient_id`) values (33, 1))
随着disease_id
增加对每个请求
嗯“正在同步关联”一节奇怪了,我做了'将gettype()'的要求,和我串?那么可能是JSON字符串。我正在尝试'json_decode()'... – Norgul
如果你'dd($ request);'? –
这是一个huuuge名单。但是,如果我做了这条线'$ diseases = array_keys(array_filter(json_decode($ request-> diseases,true)));'我再次得到完整性违规,但现在它正在用2个值(27,1)for'disease_id '和'patient_id'。第二个是没问题,第一个是每个请求递增 – Norgul