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我的问题有点傻,但我不知道该怎么做。我创建使用标准结构的标准flexigrid:如何用代码点火器中的另一个控制器的传入变量创建flexigrid?
//ver lib
/*
* 0 - display name
* 1 - width
* 2 - sortable
* 3 - align
* 4 - searchable (2 -> yes and default, 1 -> yes, 0 -> no.)
*/
$colModel['users.id'] = array('id',40,TRUE,'center',1);
$colModel['users.first_name'] = array('first_name',80,TRUE,'center',0);
$colModel['users.last_name'] = array('last_name',180,TRUE,'left',1);
$colModel['users.email'] = array('email',120,TRUE,'left',0);
$colModel['users.username'] = array('username',130, TRUE,'left',0);
$colModel['users.activation_code'] = array('activation_code',80, FALSE, 'right',0);
$colModel['users.activated'] = array('activated',80, FALSE, 'right',0);
$colModel['lists'] = array('Lists',90, FALSE, 'right',0);
/*
* Aditional Parameters
*/
$gridParams = array(
'width' => 'auto',
'height' => 400,
'rp' => 15,
'rpOptions' => '[10,15,20,25,40]',
'pagestat' => 'Displaying: {from} to {to} of {total} items.',
'blockOpacity' => 0.5,
'title' => 'Hello',
'showTableToggleBtn' => true
);
/*
* 0 - display name
* 1 - bclass
* 2 - onpress
*/
$buttons[] = array('Delete','delete','test');
$buttons[] = array('separator');
$buttons[] = array('Select All','add','test');
$buttons[] = array('DeSelect All','delete','test');
$buttons[] = array('separator');
//Build js
//View helpers/flexigrid_helper.php for more information about the params on this function
$grid_js = build_grid_js('flex1',site_url("admin/users/list_users"),$colModel,'users.first_name','asc',$gridParams,$buttons);
$data['js_grid'] = $grid_js;
$this->load->view('admin_panel/admin_content', $data);
现在我的问题是:是否有可能创建第三URI段参数的flexigrid?例如,我想显示一个列表,该列表由用户创建并执行,我需要他的ID。我可以轻松地在同一个控制器中执行该操作,但我想将它传递给不同的控制器,并在那里创建新的flexigrid表单。所以在'index()'方法我可以有,例如$ get_id变量从不同的控制器传递?喜欢这个?
$grid_js = build_grid_js('flex1',site_url("admin/admin_lists/display_show_list/".$get_id),$colModel,'name','asc',$gridParams,$buttons);
我希望我解释得很好。有人可以给我一些帮助吗?大多赞赏任何提示!
谢谢Yman的回复。很好的队友! – Pavel 2010-09-16 07:00:33
没有问题!别客气 – Yman 2010-09-16 15:06:40