和array_diff（）函数不表示正确的结果

Question

array_diff()功能无法显示正确的结果： -

第一阵列： -

 Array(
    [designation_id] => 1 
    [name] => Y 
    [fathers_name] => Z 
    [mothers_name] => F 
    [spouse_name] => d 
    [gender] => F 
    [last_achieved_degree] => 2 
    [date_of_birth] => 1960-10-17 
    [date_of_joining] => 1987-02-04 
) 

第二阵列： -

Array 
    (
     [designation_id] => 9 
     [name] => M 
     [fathers_name] => N 
     [mothers_name] => O 
     [spouse_name] => 
     [gender] => M 
     [last_achieved_degree] => 1 
     [date_of_birth] => 1967-11-17 
     [date_of_joining] => 2016-01-01 
    ) 

输出：

Array 
(
    [name] => Y 
    [fathers_name] => Z 
    [mothers_name] => F 
    [spouse_name] => d 
    [gender] => F 
    [last_achieved_degree] => 2 
    [date_of_birth] => 1960-10-17 
    [date_of_joining] => 1987-02-04 
) 

desi输出结果中没有显示gnation id列。 如果指定ID值为1，则此索引不会在输出中显示，否则显示。它是错误还是别的？

Answer 1

由于您的数组是关联数组，所以你需要使用array_diff_assoc： -

<?php 

$a = Array(
    'designation_id' =>1, 
    'name' => 'Y', 
    'fathers_name' => 'Z', 
    'mothers_name' => 'F', 
    'spouse_name' => 'd', 
    'gender' => 'F', 
    'last_achieved_degree' => 2, 
    'date_of_birth' => '1960-10-17', 
    'date_of_joining' => '1987-02-04' 
); 

$b =Array 
(
    'designation_id' => 9, 
    'name' => 'M', 
    'fathers_name' => 'N', 
    'mothers_name' => 'O', 
    'spouse_name' => '', 
    'gender' => 'M', 
    'last_achieved_degree' => 1, 
    'date_of_birth' => '1967-11-17', 
    'date_of_joining' => '2016-01-01', 
); 

echo "<pre/>";print_r(array_diff_assoc($a,$b)); 

输出： - https://eval.in/654658

，检查更多的描述和实例： - http://sg2.php.net/manual/en/function.array-diff-assoc.php

为什么array_diff()不工作： - https://stackoverflow.com/a/4742438/4248328

Answer 2

array_diff计算不区分键的差异。在第二个数组中，您有[last_achieved_degree] => 1删除[designation_id] => 1。
尝试array_diff_assoc。