vb.net使用htmlagilitypack

Question

这是HTML

<div id="catlist-listview" class="cat-listview cat-listbsize"> 
<ul> 
    <li><a href="http://wantedlink1" rel="bookmark" title="sometitel1" class="sonra">title1</a></li>  
    <li><a href="http://wantedlink2" rel="bookmark" title="sometitel2" class="sonra">title2</a></li> 
    <li><a href="http://wantedlink3" rel="bookmark" title="sometitel3" class="sonra">title3</a></li> 
    <li><a href="http://wantedlink4" rel="bookmark" title="sometitel4" class="sonra">title4</a></li> 
    <li><a href="http://wantedlink5" rel="bookmark" title="sometitel5" class="sonra">title5</a></li> 
    <li><a href="http://wantedlink6" rel="bookmark" title="sometitel6" class="sonra">title6</a></li> 
    <li><a href="http://wantedlink7" rel="bookmark" title="sometitel7" class="sonra">title7</a></li> 
    <li><a href="http://wantedlink8" rel="bookmark" title="sometitel8" class="sonra">title8</a></li> 
    <li><a href="http://wantedlink9" rel="bookmark" title="sometitel9" class="sonra">title9</a></li> 
    <li><a href="http://wantedlink10 " rel="bookmark" title="sometitel10" class="sonra">title10</a></li> 
</ul> 
</div> 

和我的代码是

dim htmldoc as new htmldocument 
htmldoc.loadhtml(source) 
for each link as htmlnode in htmldoc.document.selectnodes("//*[@id='catlist-listview']/ul") 
textbox3.text = link.innerhtml 
next 

输出

 <li><a href="http://wantedlink1" rel="bookmark" title="sometitel1" class="sonra">title1</a></li>  
     <li><a href="http://wantedlink2" rel="bookmark" title="sometitel2" class="sonra">title2</a></li> 
     <li><a href="http://wantedlink3" rel="bookmark" title="sometitel3" class="sonra">title3</a></li> 
     <li><a href="http://wantedlink4" rel="bookmark" title="sometitel4" class="sonra">title4</a></li> 
     <li><a href="http://wantedlink5" rel="bookmark" title="sometitel5" class="sonra">title5</a></li> 
     <li><a href="http://wantedlink6" rel="bookmark" title="sometitel6" class="sonra">title6</a></li> 
     <li><a href="http://wantedlink7" rel="bookmark" title="sometitel7" class="sonra">title7</a></li> 
     <li><a href="http://wantedlink8" rel="bookmark" title="sometitel8" class="sonra">title8</a></li> 
     <li><a href="http://wantedlink9" rel="bookmark" title="sometitel9" class="sonra">title9</a></li> 
     <li><a href="http://wantedlink10 " rel="bookmark" title="sometitel10" class="sonra">title10</a></li> 

我想要得到一切，只获得所有属性值http://wantedlink1到http://wantedlink10 我尝试属性（“href”），但我只有一个链接 我想列出所有这样的链接：

http://wantedlink1 
http://wantedlink2 
http://wantedlink3 
. 
. 
. 
http://wantedlink10 

任何帮助？

Answer 1

基本上，您可以更改XPath为SelectNodes()选择单个<a>元素而不是<ul>。然后从这一点开始，将很容易遍历结果并逐个获取属性。或者你使用LINQ，例如像以下实现相同的：

'select <a> elements' 
Dim links = htmldoc.Document.SelectNodes("//*[@id='catlist-listview']/ul/li/a") 
'project to IEnumerable of href attribute value' 
Dim hrefs = links.Cast(Of HtmlNode)().Select(Function(x) x.GetAttributeValue("href", "")) 
'join the `hrefs`, separated by newline, into one string' 
textbox3.text = String.Join(Environment.NewLine, hrefs) 

dotnetfiddle demo