从Instagram API,您应该使用链接参数来获取每张照片的链接。这个代码应该在里面成功(数据)函数。使用/用户/自/媒体/最近端点将大概叫这样的:
[...]
success: function(data){
for (i = 0; i < data.length; i++){
var photoURL = data[i].images.standard_resolution.url;
var photoLink = data[i].link;
var username = data[i].user.username;
var html = "<a href='" + photoLink + "' target='_blank'>";
html += " <img src='" + photoURL + "' alt='" + username + "'>";
html += "</a>";
// here you should append this html code to some container box
document.getElementById("myContainer").innerHTML += html;
}
}
这上面的代码并没有进行测试。但我相信它工作正常。 以下是media object returned by Instagram,所以你可以选择你需要的任何信息。我隐藏了users_in_photo和images部分以便于理解。
{
"data": {
"type": "image",
"users_in_photo": [{...}],
"filter": "Walden",
"tags": [],
"comments": { "count": 2 },
"caption": null,
"likes": { "count": 1 },
"link": "http://instagr.am/p/D/",
"user": {
"username": "kevin",
"full_name": "Kevin S",
"profile_picture": "...",
"id": "3"
},
"created_time": "1279340983",
"images": {...},
"id": "3",
"location": null
}
}
用户在照片部分:
"users_in_photo": [{
"user": {
"username": "kevin",
"full_name": "Kevin S",
"id": "3",
"profile_picture": "..."
},
"position": {
"x": 0.315,
"y": 0.9111
}
}],
图片部分:
"images": {
"low_resolution": {
"url": "http://distillery.s3.amazonaws.com/media/2010/07/16/4de37e03aa4b4372843a7eb33fa41cad_6.jpg",
"width": 306,
"height": 306
},
"thumbnail": {
"url": "http://distillery.s3.amazonaws.com/media/2010/07/16/4de37e03aa4b4372843a7eb33fa41cad_5.jpg",
"width": 150,
"height": 150
},
"standard_resolution": {
"url": "http://distillery.s3.amazonaws.com/media/2010/07/16/4de37e03aa4b4372843a7eb33fa41cad_7.jpg",
"width": 612,
"height": 612
}
},
祝你好运!
您是否在寻找图片或帖子的网址? –
@TariqB。帖子的网址。 Sry我的错误 –
数据对象中的链接参数应该是该帖子的URL。请尝试。 –