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我试图用HTTP POST动作的响应主体的工作,我采取了以下方法:问题Apache的HttpClient的越来越响应当
公共类POST2 {
public final static void main(String[] args) throws Exception {
CloseableHttpClient httpclient = HttpClients.createDefault();
List<NameValuePair> formparams = new ArrayList <NameValuePair>();
formparams.add(new BasicNameValuePair("login_id", myID));
formparams.add(new BasicNameValuePair("api_key", myKey));
UrlEncodedFormEntity entity = new UrlEncodedFormEntity(formparams, Consts.UTF_8);
HttpPost httppost = new HttpPost(myURL);
httppost.setEntity(entity);
CloseableHttpResponse response2 = httpclient.execute(httppost);
try{
System.out.println(response2.getStatusLine());
HttpEntity entity2 = response2.getEntity();
EntityUtils.consume(entity2);
String responseBody = EntityUtils.toString(entity2);
System.out.println("finalResult"+responseBody.toString());
}
finally {
httpclient.close();
}
}
}
我只是接收 “HTTP/1.1 200 OK”,随后
异常在线程 “主要” java.lang.ClassCastException:org.apache.http.impl.execchain.HttpResponseProxyç annot be cast to org.apache.http.HttpEntity at post2.main(post2.java:62)
我应该如何从WebService恢复正文信息?
谢谢, 利奥
得到它...不得不移动EntityUtils.consume(ENTITY2);到块的底部... – lscesario